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3 years ago

I need help please?!!!

Mathematics

1 answer:

lilavasa [31]3 years ago

3 0

Answer:

True

Step-by-step explanation:

If the line is solid, it is part of the solution; if it is dotted or dashed, it is not. Solid is ≥ ≤ while dashed is > <

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6x + y = -2 y= -3x + 1 Graph the solution

Gala2k [10]

6x + y = -2
y = -3x + 1

Substitute the value of y in first equation,
6x -3x + 1 = -2
3x = -2-1
x = -3/3
x = -1

Now, Substitute it in 2nd equation,
y = -3(-1) + 1
y = 3+ 1 = 4

Coordinates would be: (-1,4) Mark that point and join with origin.

Hope this helps!

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3 years ago

Keenan gives tisha half of his strawberries. tisha keeps 4 of the strawberries she got from keenan and gives the rest to suvi. w

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At start Keenan has x strawberries. He gives Tisha x/2. Then Tisha keeps 4 strawberries and gives Suvi the rest. If y is the number of strawberries that Suvi gets:
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6 = 20/2 - 4
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3 years ago

The graph of y=-3x+4 is: pls pls pls help

frutty [35]

Answer:

D. A line that shows only one solution to the equation

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Mrs. chin paid a 20 percent tip on the bill for lunch.if the tip amount was $2.75, what was the bill for lunch before the tip wa

bija089 [108]

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Read 2 more answers

A polygon is shown: A polygon MNOPQR is shown. The top vertex on the left is labeled M, and rest of the vertices are labeled clo

Mashcka [7]

Answer:

The area of polygon MNOPQR = Area of a rectangle that is 15 square units + Area of a rectangle that is 2 square units.

Step-by-step explanation:

We are given that a polygon MNOPQR is shown. The top vertex on the left is labeled M, and the rest of the vertices are labeled clockwise starting from the top-left vertex labeled, M. The side MN is parallel to side QR. The side MR is parallel to side PQ.

The side MN is labeled as 5 units. The side QR is labeled as 7 units. The side MR is labeled as 3 units, and the side NO is labeled as 2 units.

Firstly, we will draw a perpendicular line from point O which meets the line RQ at point T. Now, the polygon MNOPQR is divided into two rectangles MNTR and OPQT.

As we know that the area of the rectangle = $\text{Length of rectangle} \times \text{Breadth of rectangle}$

In the rectangle MNTR, the length (MN) = 5 units and the breadth (MR) = 3 units.

So, the area of the rectangle MNTR = $\text{Length (MN)} \times \text{Breadth (MR)}$

= $5 \times 3$ = 15 square units

Now, as we know that in rectangle MNTR, the side NT = 3 units and the side NO is labeled as 2 units. This means that the side OT = NT - NO = 3 units - 2 units = 1 unit

Similarly, the side QR is labeled as 7 units and the side RT is labeled as 5 units. This means that the side TQ = QR - RT = 7 - 5 = 2 units

Now, in the rectangle OPQT, the length (TQ) = 2 unit and the breadth (OT) = 2 units.

So, the area of the rectangle OPTQ = $\text{Length (TQ)} \times \text{Breadth (OT)}$

= $2 \times 1$ = 2 square units

Hence, the area of polygon MNOPQR = Area of a rectangle that is 15 square units + Area of a rectangle that is _2_ square units.

3 0

3 years ago