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larisa86 [58]
3 years ago
13

Which of the following is the most reasonable product of 5 10/11 and 3 16/17

Mathematics
1 answer:
Lilit [14]3 years ago
7 0

Answer:

24

Step-by-step explanation:

Both improper fractions are very close to the next whole number, and since it asks for the most reasonable product (multiply/times) you can round them both up to 6 and 4. 6 x 4= 24

You might be interested in
Prove whether the quadrilateral is a parallelogram using the Distance & Slope Formulas D(-5, -6), E(5, 2), F(4, -4), G(-6, -
amm1812

Answer:

See the distances bellow

Step-by-step explanation:

Given data

D(-5, -6), E(5, 2)

substitute into the expression for the distance

d= \sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2)\\\\d= \sqrt((5+5)^2 + (2+6)^2)\\\\d= \sqrt((10)^2 + (8)^2)\\\\d= \sqrt(100 +64)\\\\d= \sqrt((164)\\\\d= 12.80

E(5, 2), F(4, -4)

d= \sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2)\\\\d= \sqrt((4-5)^2 + (-4-2)^2)\\\\d= \sqrt((-1)^2 + (-6)^2)\\\\d= \sqrt(1+36)\\\\d= \sqrt((37)\\\\d= 6.08

F(4, -4), G(-6, -12)

d= \sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2)\\\\d= \sqrt((-6-4)^2 + (-12+4)^2)\\\\d= \sqrt((-10)^2 + (-8)^2)\\\\d= \sqrt(100+64)\\\\d= \sqrt((164)\\\\d= 12.80

G(-6, -12),  D(-5, -6)

d= \sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2)\\\\d= \sqrt((-6+5)^2 + (-12+6)^2)\\\\d= \sqrt((-1)^2 + (-6)^2)\\\\d= \sqrt(1+36)\\\\d= \sqrt((37)\\\\d= 6.08

8 0
3 years ago
3(0)+2y=1. Help plzzz
vladimir1956 [14]

Answer:

y=.5 or y=1/2

Step-by-step explanation:

3(0)+2y=1

3 x 0 = 0

0 + 2y = 1

2y = 1

Divide by 2

y=.5 or y=1/2

5 0
3 years ago
If you walk 3 miles a day every day how many feet per hour can you walk in 2 weeks
dusya [7]
I think the answer is 221,760
4 0
4 years ago
Show all steps used to solve the problem 4x+6<-6
mel-nik [20]

The answer is x<-3

Step-by-step explanation:

4x+6<-6

-6 -6

4x>-12

÷4x. ÷4×

x<-3

4 0
3 years ago
What is the area of a rectangle with width 2/5 inches and length 3/5 inches?
Marat540 [252]
Multiply the length and width together:
 
          3        2          6
A = ------ * ------ = --------
          5        5         25

None of the given possible answers make any sense.  Please ensure that you have copied down this problem exactly as presented.

If the width were 2/5 in and the length 3/5 in, then, using decimal fractions, the area would be

A = 0.4(0.6) = 0.24 in^2, which is miles and miles away from 15 in^2 (for example)


8 0
3 years ago
Read 2 more answers
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