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3 years ago

Please help me this is due soon!!!

Mathematics

1 answer:

Tamiku [17]3 years ago

3 0

C. because the sides of the triangle are eaqule but the bottom is longet

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What is the sum of 236 and 493?

juin [17]

236 plus 493 equals 729

8 0

4 years ago

Read 2 more answers

Im struggling and need help fast please show work and tell me how to do it. no links

kow [346]

Answer:

-3.8=n

Step-by-step explanation:

My goal is to get n all by itself, but its multiplied by 6. If I do the inverse operation (which is division) on both sides I will get -22.8/6=n. Now I can just simply combine the like terms and finalize my answer. 6 * 3=18 but -22.8 is a decimal number so my answer will range from around 3.5-3.9. if I divide -22.8/6 I get -3.8. My final answer is n=-3.8

5 0

3 years ago

For each random variable defined here, describe the set of possible values for the variable, and state whether the variable is d

Blababa [14]

Answer:

Step-by-step explanation:

A discrete variable is one which can be counted or which can be associted with the set of natural numbers.

A continuous variable is one which cannot be counted.

a. of unbroken eggs in a randomly chosenstandard egg carton

--Discrete

b. of students on a class list for a particular course who are absent on the first day of classes

----Discrete

c. of times a duffer has to swing at a golfball before hitting it

----Discrete

d. of a randomly selected rattlesnake

--Continuous

e. of royalties earned from the sale of a firstedition of 10,000 textbooks

--Continuous

f. of a randomly chosen soil sample

--Continuous

g. (psi) at which a randomly selected tennisracket has been strung

--Continuous

h. number of coin tosses required for threeindividuals to obtain a match (HHH or TTT)

---Discrete

4 0

4 years ago

Multiply 2x(x2 + 5).

Irina18 [472]

Distributive property

2x^3 + 10x

3 0

3 years ago

Read 2 more answers

The given matrix is the augmented matrix for a linear system. Use technology to perform the row operations needed to transform t

shtirl [24]

Answer:

$x_{1} = \frac{176}{127} + \frac{71}{127}x_{4}\\\\ x_{2} = \frac{284}{127} + \frac{131}{254}x_{4}\\\\x_{3} = \frac{845}{127} + \frac{663}{254}x_{4}\\$

Step-by-step explanation:

As the given Augmented matrix is

$\left[\begin{array}{ccccc}9&-2&0&-4&:8\\0&7&-1&-1&:9\\8&12&-6&5&:-2\end{array}\right]$

Step 1 :

$r_{1}$ ↔ $r_{1} - r_{2}$

$\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&7&-1&-1&:9\\8&12&-6&5&:-2\end{array}\right]$

Step 2 :

$r_{3}$ ↔ $r_{3} - 8r_{1}$

$\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&7&-1&-1&:9\\0&124&-54&77&:-82\end{array}\right]$

Step 3 :

$r_{2}$ ↔ $\frac{r_{2}}{7}$

$\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&124&-54&77&:-82\end{array}\right]$

Step 4 :

$r_{1}$ ↔ $r_{1} + 14r_{2}$ , $r_{3}$ ↔ $r_{3} - 124r_{2}$

$\left[\begin{array}{ccccc}1&0&4&-11&:-8\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&0&- \frac{254}{7} &\frac{663}{7} &:-\frac{1690}{7} \end{array}\right]$

Step 5 :

$r_{3}$ ↔ $\frac{r_{3}. 7}{254}$

$\left[\begin{array}{ccccc}1&0&4&-11&:-8\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&0&1&-\frac{663}{254} &:-\frac{1690}{254} \end{array}\right]$

Step 6 :

$r_{1}$ ↔ $r_{1} - 4r_{3}$ , $r_{2}$ ↔ $r_{2} + \frac{1}{7} r_{3}$

$\left[\begin{array}{ccccc}1&0&0&-\frac{71}{127} &:\frac{176}{127} \\0&1&0&-\frac{131}{254} &:\frac{284}{127} \\0&0&1&-\frac{663}{254} &:\frac{845}{127} \end{array}\right]$

∴ we get

$x_{1} = \frac{176}{127} + \frac{71}{127}x_{4}\\\\ x_{2} = \frac{284}{127} + \frac{131}{254}x_{4}\\\\x_{3} = \frac{845}{127} + \frac{663}{254}x_{4}\\$

6 0

3 years ago