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2 years ago

12

Find the total amount in the compound interest account 1000 is compounded annually at a rate of 11% for 7 years round to the nea

rest cent

1 answer:

Elza [17]2 years ago

7 0

Answer:

The answer is 400

Step-by-step explanation:

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What are the first and last terms of this geometric series

11Alexandr11 [23.1K]

ANSWER

E. 10 and 640

EXPLANATION

The given series is

$\sum_{i=1}^45 \times 2^{2i-1}$

To find the first term of the series we substitute i=1 to get,

$a_1 = 5 \times {2}^{2 \times 1 - 1}$

$a_1 = 5 \times {2}^{ 1} = 10$

For the last term of the series, we substitute i=4 to obtain,

$a_4 = 5 \times {2}^{2 \times 4 - 1}$

$a_4 = 5 \times {2}^{7}$

This implies that,

$a_4 = 5 \times 128 = 640$

Therefore the correct answer is E

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3 years ago

Calculating Areas of Multiple Polygons

zhuklara [117]

Answer:

the answer is 29

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Joshua has (10+6a^2-5a) dollars in his savings account. Maranda had (4a^2a+3) dollars in her saving account how much more money

solniwko [45]

Answer:

Joshua has 2a^2 -6a + 7 more than Maranda.

Step-by-step explanation:

Joshua has 6a^2 -5a + 10 dollars and Maranda has 4a^2 + a + 3 to find out how much more money Joshua has we need to subtract the amount he has by the amount of Maranda's account. Since both expressions are pollynomial we'll have to subtract the numbers wich are multiplying the same power, so we do as follow:

6a^2 - 5a + 10 - (4a^2 + a + 3)

6a^2 - 5a + 10 - 4a^2 -a -3

6a^2 - 4a^2 -5a -a + 10 -3

2a^2 -6a + 7

Joshua has 2a^2 -6a + 7 more than Maranda.

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2 years ago

Read 2 more answers

Is the following conditional true?

liubo4ka [24]

Yes

Explanation:
2x9=18 and 1+8=9

The pattern repeats

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3 years ago

Read 2 more answers

Because of staffing decisions, managers of the Gibson-Marion Hotel are interested in the variability in the number of rooms occu

olchik [2.2K]

Answer:

a) $s^2 =30^2 =900$

b) $\frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}$

$567.28 \leq \sigma^2 \leq 1690.224$

c) $23.818 \leq \sigma \leq 41.112$

Step-by-step explanation:

Assuming the following question: Because of staffing decisions, managers of the Gibson-Marimont Hotel are interested in the variability in the number of rooms occupied per day during a particular season of the year. A sample of 20 days of operation shows a sample mean of 290 rooms occupied per day and a sample standard deviation of 30 rooms

Part a

For this case the best point of estimate for the population variance would be:

$s^2 =30^2 =900$

Part b

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$

The degrees of freedom are given by:

$df=n-1=20-1=19$

Since the Confidence is 0.90 or 90%, the significance $\alpha=0.1$ and $\alpha/2 =0.05$ , the critical values for this case are:

$\chi^2_{\alpha/2}=30.144$

$\chi^2_{1- \alpha/2}=10.117$

And replacing into the formula for the interval we got:

$\frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}$

$567.28 \leq \sigma^2 \leq 1690.224$

Part c

Now we just take square root on both sides of the interval and we got:

$23.818 \leq \sigma \leq 41.112$

5 0

3 years ago