Answer:
The correct answer is J. 10
Step-by-step explanation:
The answer to the equation 4/5 divided by 2/25 is equal to 10.
The solutions to the given system of equations is (0, -6) and (1, -5)
<h3>Simultaneous equations</h3>
From the question, we are to determine the solutions to the given system of equations
The equations are
x − y = 6 --------- (1)
y = x² −6 ---------- (2)
From equation (1)
x - y = 6
∴ x = 6 + y ------- (3)
Substitute into equation (2)
y = x² −6
y = (6+y)² −6
y = (6+y)(6+y) -6
y = 36 + 6y + 6y +y² -6
y = 36 + 12y + y² - 6
Simplifying
y² + 12y - y + 30 = 0
y² + 11y + 30 = 0
Solve quadratically
y² + 11y + 30 = 0
y² + 6y + 5y + 30 = 0
y(y +6) +5 (y +6) = 0
(y + 5)(y + 6) = 0
y + 5 = 0 OR y + 6 = 0
y = -5 OR y = -6
Substitute the values of y into equation (3)
x = 6 + y
When y = -5
x = 6 + (-5)
x = 6 -5
x = 1
When y = -6
x = 6 + (-6)
x = 6 -6
x = 0
∴ When x = 0, y = -6 and when x = 1, y = -5
Hence, the solutions to the given system of equations is (0, -6) and (1, -5)
Learn more on Solving simultaneous equations here: brainly.com/question/16863577
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Answer:
y = 4
Step-by-step explanation:
Note that A and B have the same x-coordinate: 1. This means that AB is a vertical line through x = 1. The perpendicular bisector of AB must be a horizontal line situated halfway between y = 3 and y = 5. Thus, it's just y = 4.
Review: y = 4 bisects AB and represents a horizontal line.
Answer: RI 18,823.14
Step-by-step explanation:
I guess that we want to find the 12.6% of Rl 149,390
First, we assume that Rl 149,390 is the 100%
Then we can write an equation like:
Rl 149,390 = 100%
Then if the amount X is the 12.6%, we also have the equation:
X = 12.6%
Then we have the two equations:
X = 12.6%
Rl 149,390 = 100%
If we take the quotient between these two equations we get:
(X/Rl 149,390) = (12.6%/100%)
Solving this for X we get:
X = (12.6%/100%)*(Rl 149,390) = RI 18,823.14
Answer:
Step-by-step explanation:
We are told the school sold raffle tickets, and each ticket has a digit either 1, 2, or 3. The school also sold 2 tickets with the number 000.
Therefore we have the following raffle tickets:
123
132
213
231
312
321
000
000
From the given information, we can deduce that the school sold 8 tickets and only one ticket can contain the number arrangement of 123, but 000 appeared twice.
Probability of 123 to be picked=
1/8 => 0.125
Probability of 000 to be picked=
2/8 => 0.25
Since the probability of 000 to be picked is greater than 123, a ticket number of 000 is more likely to be picked
