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love history [14]
3 years ago
7

a sled regular sells for $400 but is now on sale for $280. by how much has the price of the sled been decreased

Mathematics
1 answer:
Tomtit [17]3 years ago
7 0
It has been decreased by $120
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Use a number line to name two numbers that are the same distance apart as 3.2 and 4.4.
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Answer:

3.3 and 4.5

Step-by-step explanation:

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4 years ago
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An investment project involves an immediate outlay of $8 million. The net cash flows received at the end of years 1, 2, and 3 wi
My name is Ann [436]

Answer:

(c) 0.46 million

Step-by-step explanation:

As provided immediate cash outlay = $8 million.

This will represent cash outflow at period 0, as it is made immediately, no time period has lapsed.

Cash inflows as provided and the respective present value factor are:

Year         Cash Inflow       Factor              Discounted Value

1                 $3 million         0.9091                $2,727,300

2                $4 million         0.8264               $3,305,600

3                 $2 million         0.7513                $1,502,600

Total present value of cash inflow = $7,535,500

Therefore, net present value = $7,535,500 - $8,000,000 = - $464,500

That is - 0.46 million

Correct option is

(c) 0.46 million

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3 years ago
Which equation in point-slope form describes the line through points (4, –4) and (1, 2)?
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Step-by-step explanation:

<em>Given </em><em>points </em><em>(</em><em>4</em><em> </em><em>,</em><em> </em><em>-</em><em>4</em><em>)</em><em> </em><em> </em><em>and </em><em>(</em><em> </em><em>1</em><em>,</em><em> </em><em>2</em><em>)</em>

<em>First </em><em>calculating </em><em>slope </em><em>(</em><em>m) </em><em> </em>

<em>=</em><em>(</em><em> </em><em>y2</em><em> </em><em>-</em><em> </em><em>y1) </em><em>/</em><em>(</em><em> </em><em>x2 </em><em>-</em><em>x1) </em>

<em>=</em><em> </em><em>(</em><em> </em><em>2</em><em> </em><em>+</em><em> </em><em>4</em><em>)</em><em> </em><em>/</em><em> </em><em>(</em><em>1</em><em>-</em><em>4</em><em>)</em>

<em>=</em><em> </em><em>6</em><em>/</em><em> </em><em>-</em><em>3</em>

<em>=</em><em> </em><em>-</em><em>2</em>

<em>Now</em>

<em>The </em><em>equation </em><em>in </em><em>point </em><em>slope </em><em>form</em>

<em>y </em><em>-</em><em> </em><em>y1</em><em> </em><em>=</em><em> </em><em>m </em><em>(</em><em> </em><em>x </em><em>-</em><em> </em><em>x1) </em>

<em>y </em><em>+</em><em> </em><em>4</em><em> </em><em>=</em><em> </em><em>-</em><em>2</em><em> </em><em>(</em><em> </em><em>x </em><em>-</em><em> </em><em>4</em><em>)</em>

<em>y </em><em>+</em><em> </em><em>4</em><em> </em><em>=</em><em> </em><em>-</em><em>2</em><em>x</em><em> </em><em>+</em><em> </em><em>8</em>

<em>2x </em><em>+</em><em> </em><em>y </em><em>-</em><em> </em><em>8</em><em> </em><em>+</em><em> </em><em>4</em><em> </em><em>=</em><em> </em><em>0</em>

<em>2x </em><em>+</em><em> </em><em>y </em><em>-</em><em>4</em><em> </em><em>=</em><em> </em><em>0</em><em> </em><em>which </em><em>is </em><em>the </em><em>required </em><em>equation </em>

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