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elena55 [62]
3 years ago
10

Type the correct answer in the box

Mathematics
1 answer:
tekilochka [14]3 years ago
6 0

Answer:

126 pie cubic inches.

Step-by-step explanation:

i dont have one^ but i completed the test with a 100%

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In the triangle pictured, let A, B, C be the angles at the three vertices, and let a,b,c be the sides opposite those angles. Acc
Troyanec [42]

Answer:

Step-by-step explanation:

(a)

Consider the following:

A=\frac{\pi}{4}=45°\\\\B=\frac{\pi}{3}=60°

Use sine rule,

\frac{b}{a}=\frac{\sinB}{\sin A}
\\\\=\frac{\sin{\frac{\pi}{3}}
}{\sin{\frac{\pi}{4}}}\\\\=\frac{[\frac{\sqrt{3}}{2}]}{\frac{1}{\sqrt{2}}}\\\\=\frac{\sqrt{2}}{2}\times \frac{\sqrt{2}}{1}=\sqrt{\frac{3}{2}}

Again consider,

\frac{b}{a}=\frac{\sin{B}}{\sin{A}}
\\\\\sin{B}=\frac{b}{a}\times \sin{A}\\\\\sin{B}=\sqrt{\frac{3}{2}}\sin {A}\\\\B=\sin^{-1}[\sqrt{\frac{3}{2}}\sin{A}]

Thus, the angle B is function of A is, B=\sin^{-1}[\sqrt{\frac{3}{2}}\sin{A}]

Now find \frac{dB}{dA}

Differentiate implicitly the function \sin{B}=\sqrt{\frac{3}{2}}\sin{A} with respect to A to get,

\cos {B}.\frac{dB}{dA}=\sqrt{\frac{3}{2}}\cos A\\\\\frac{dB}{dA}=\sqrt{\frac{3}{2}}.\frac{\cos A}{\cos B}

b)

When A=\frac{\pi}{4},B=\frac{\pi}{3}, the value of \frac{dB}{dA} is,

\frac{dB}{dA}=\sqrt{\frac{3}{2}}.\frac{\cos {\frac{\pi}{4}}}{\cos {\frac{\pi}{3}}}\\\\=\sqrt{\frac{3}{2}}.\frac{\frac{1}{\sqrt{2}}}{\frac{1}{2}}\\\\=\sqrt{3}

c)

In general, the linear approximation at x= a is,

f(x)=f'(x).(x-a)+f(a)

Here the function f(A)=B=\sin^{-1}[\sqrt{\frac{3}{2}}\sin{A}]

At A=\frac{\pi}{4}

f(\frac{\pi}{4})=B=\sin^{-1}[\sqrt{\frac{3}{2}}\sin{\frac{\pi}{4}}]\\\\=\sin^{-1}[\sqrt{\frac{3}{2}}.\frac{1}{\sqrt{2}}]\\\\\=\sin^{-1}(\frac{\sqrt{2}}{2})\\\\=\frac{\pi}{3}

And,

f'(A)=\frac{dB}{dA}=\sqrt{3} from part b

Therefore, the linear approximation at A=\frac{\pi}{4} is,

f(x)=f'(A).(x-A)+f(A)\\\\=f'(\frac{\pi}{4}).(x-\frac{\pi}{4})+f(\frac{\pi}{4})\\\\=\sqrt{3}.[x-\frac{\pi}{4}]+\frac{\pi}{3}

d)

Use part (c), when A=46°, B is approximately,

B=f(46°)=\sqrt{3}[46°-\frac{\pi}{4}]+\frac{\pi}{3}\\\\=\sqrt{3}(1°)+\frac{\pi}{3}\\\\=61.732°

8 0
3 years ago
Enzel goes online to buy a graphing calculator. He finds a site that currently has a promotion of 15% off on all orders over $50
Sonbull [250]

Based on the cost of the calculator, the discount, the shipping fee, and the tax, the total cost of the purchase was<u> a. $80.07</u>

The cost of the calculator was:

<em>= Cost of calculator x ( 1  - discount)</em>

= 83 x ( 1 - 15%)

= $70.55

The sales tax would be:

= 70.55 x 4.5%

= $3.17

The total cost would be:

<em>= Cost + Sales tax + Shipping fee</em>

= 70.55 + 3.17 + 6.35

= $80.07

In conclusion, the total is $80.07.

<em>Find out more on such at brainly.com/question/11239587. </em>

8 0
2 years ago
A square base of a pyramid has the dimensions 5 yards
AfilCa [17]

Answer:

145 yd²

Step-by-step explanation:

There will be dour triangular faces. For a triangle, area is given as

A=½bh where b is base and h is height. The base will be 5 yards and h is 12 yards hence for one triangular face, area will be ½*5*12=30 yd²

Since they are four similar triangles, area of triangular faces will be 30*4=120 yd²

The surface area of a square base is given by

A=a*a=a² where a is the dimension of one side. Given that the meaurement is 5 yards then A=5²=25 yd²

Total area will be the sum of triangular and square faces hence 120+25=145 yd²

7 0
3 years ago
Read 2 more answers
Two numbers have a difference of 0.85 and a sum of 1 what are the numbers?
soldier1979 [14.2K]
X - y = 0.85
x + y = 1
----------------add
2x = 1.85
x = 1.85/2
x = 0.925

x + y = 1
0.925 + y = 1
y = 1 - 0.925
y = 0.075

so ur 2 numbers are : 0.925 and 0.075
3 0
3 years ago
Read 2 more answers
5. Mis the midpoint of CD. C has coordinates (-1,-1) and
lana66690 [7]

Answer/Step-by-step Explanation:

4. Midpoint (M) of AB, for A(-2, -3) and B(1, 2) is given as:

M(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2})

Let A(-2, -3) = (x_1, y_1)

B(1, 2) = (x_2, y_2)

Thus:

M(\frac{-2 + 1}{2}, \frac{-3 + 2}{2})

M(\frac{-1}{2}, \frac{-1}{2})

5. Given M(3, 5) as midpoint of CD, and C(-1, -1),

let C(-1, -1) = (x_2, y_2)

D(?, ?) = (x_1, y_1)

M(3, 5) = (\frac{x_1 +(-1)}{2}, \frac{y_1 +(-1)}{2})

Rewrite the equation to find the coordinates of D

3 = \frac{x_1 - 1}{2} and 5 = \frac{y_1 - 1}{2}

Solve for each:

3 = \frac{x_1 - 1}{2}

3*2 = \frac{x_1 - 1}{2}*2

6 = x_1 - 1

6 + 1= x_1 - 1 + 1

7 = x_1

x_1 = 7

5 = \frac{y_1 - 1}{2}

5*2 = \frac{y_1 - 1}{2}*2

10 = y_1 - 1

10 + 1= y_1 - 1 + 1

11 = y_1

y_1 = 11

Coordinates of D is (7, 11)

7 0
3 years ago
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