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andreyandreev [35.5K]
3 years ago
6

The function -6t^2+5t+56=h is used to calculate the amount of time (t) in seconds it takes for an object to reach a certain heig

ht (h). According to this function, how many seconds will it take for the object to hit the ground?
Mathematics
1 answer:
seraphim [82]3 years ago
6 0

Answer:

3.5 seconds

Step-by-step explanation:

h(t) is a quadratic function, it indicate that the object start with initial height (56).

If you want to know when the object hit the ground (h=0) you have to use the quadratic formula (-b +- \sqrt{b^{2}-4ac } )/2a and take the positive root (the negative shows a negative time, so we have to discard it).

In this case: a=-6, b=5 and c=56, then the solve is 7/2=3.5

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I need help on number 2
Nina [5.8K]

9514 1404 393

Answer:

  a. 405

  b. -2

  c. 5

  d. 43

Step-by-step explanation:

I don't like doing arithmetic any more than you do, so I let a calculator do it for me. A spreadsheet works well for this, too. The function values are shown in the attachment.

Put the function argument where the variable is and do the arithmetic.

  a. h(4) = 5·3^4 = 405

  b. d(2) = 7 -9(2 -1) = -2

  c. h(0) = 5·3^0 = 5

  d. d(-3) = 7 -9(-3 -1) = 43

7 0
3 years ago
A construction crew is lengthening a road. The road started with a length of 54 miles, and the crew is adding 3 miles to the roa
patriot [66]
53+3(D) = L

53 + 3(38) =L

53 +114 = L

167=L
6 0
3 years ago
TRUE or FALSE: In the quarter circle, the radius is 4 cm and the diameter is 8 cm.
viktelen [127]

Answer: False.

Step-by-step explanation:

There does not exist a "quarter circle" as a circle with a radius of 4 units, the only notable circle that does exist is the unit circle, that is the circle where the radius is equal to 1, represented by the equatin x^2 + y^2 = 1

The term "quarter circle" actually does refer to a fourth part of a circle, not to a circle of radius 4.

So the statement is false

6 0
3 years ago
Suppose triangle ABC has vertices at A(1, 0), B(10, 0), and C(2, 6). After a 60° counterclockwise rotation about the origin, ver
Artemon [7]
Check the picture attached.

Let OB be the radius of circle with center O.

Let B' be the image of B after the described rotation

OB and OB' are sides of the equilateral triangle OBB'.

The x coordinate of B' is the midpoint of OB, that is 5.

In the right triangle B', point (5, 0) and B:

Distance point (5, 0) to B is 5
|B'B|=|OB|=10

so by the pythagorean theorem:

a= \sqrt{ 10^{2} - 5^{2} } = \sqrt{ 2^{2} *5^{2} - 5^{2} }= \sqrt{5^{2}(4-1)}=5 \sqrt{3} units



Answer: 5 \sqrt{3}

3 0
3 years ago
Literal Equations? Anyone? The problems are in the picture! Show solution please! Thanks in advance!
lapo4ka [179]
The way to solve is using order of operation PEMDAS. Its very easy. You should be able to solve it yourself. I'll give you the first 3 answers: 
1. g/6=x
2. x=1/2u+1
3. z-m=x
I would give you all the answers but it would be best if you did it yourself. You teacher and parents would be much happier if you learnt the skill. Hope this answer helps! Mark as brainliest! :)
4 0
3 years ago
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