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3 years ago

Choose an equation for the relationship between the measures of the segments, angles, and arcs.

Mathematics

2 answers:

elixir [45]3 years ago

7 0

Answer:

m∠QPR = $\frac{1}{2}$ ( arc QTR - arc QSR) would be the relation between segments, angles, and arcs.

Step-by-step explanation:

Given : A circle with two secant QP and RP and larger arc QTR , smaller QSR.

To find : An equation for the relationship between the measures of the segments, angles, and arcs.

Solution : We have given that A circle with two secant QP and RP and arc QTR , QSR.

Angle by two secant = $\frac{1}{2}$ ( larger arc -smaller arc)

So, the relation between segments, angles, and arcs by diagram is :

m∠QPR = $\frac{1}{2}$ ( arc QTR - arc QSR).

Therefore, m∠QPR = $\frac{1}{2}$ ( arc QTR - arc QSR) would be the relation between segments, angles, and arcs.

Maru [420]3 years ago

6 0

The answer would be the second one, (measure QPR is equal to 1/2(QTR - QR). Same as the first question you ask, just use the (large arc - small arc)/2 formula.

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If the discriminant of a quadratic equation is equal to -8, which statement describes the roots?

Dovator [93]

Keywords

quadratic equation, discriminant, complex roots, real roots

we know that

The formula to calculate the roots of the quadratic equation of the form $ax^{2} +bx+c=0$ is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}}{2a}$

where

The discriminant of the quadratic equation is equal to

$b^{2}-4ac$

if $(b^{2}-4ac)> 0$ ----> the quadratic equation has two real roots

if $(b^{2}-4ac)=0$ ----> the quadratic equation has one real root

if $(b^{2}-4ac)< 0$ ----> the quadratic equation has two complex roots

in this problem we have that

the discriminant is equal to $-8$

the quadratic equation has two complex roots

therefore

the answer is the option A

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5 0

3 years ago

Read 2 more answers

What is the answer? Some please help!!

Aleksandr [31]

Answer:

Area of the figure = 200 cm²

Step-by-step explanation:

Area of rectangle A = Length × Width

= 5×9

= 45 cm²

Area of rectangle B = 5 × 11

= 55 cm²

Area of rectangle C = 5 × 9

= 45 cm²

Area of rectangle D = 5 × 7

= 35 cm²

Area of rectangle E = 10 × 2

= 20 cm²

Total area of the figure = 45 + 55 + 45 + 35 + 20

= 200 cm²

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3 years ago

Questions 5)

artcher [175]

Answer:

the answer is for the question you are asking is A) Atom

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3 years ago

A sample of 100 workers located in Atlanta has an average daily work time of 6.5 hours with a standard deviation of 0.5 hours. A

Readme [11.4K]

Answer:

$t=\frac{6.5-6.7}{\sqrt{\frac{0.5^2}{100}+\frac{0.7^2}{110}}}}=-2.398$

$df = n_1 +n_2 -2= 100+110-2= 208$

Since is a bilateral test the p value would be:

$p_v =2*P(t_{208}$

Comparing the p value with the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we can reject the null hypothesis, and we have significant differences between the two groups at 5% of significance.

Step-by-step explanation:

Data given and notation

$\bar X_{1}=6.5$ represent the sample mean for Atlanta

$\bar X_{2}=6.7$ represent the sample mean for Chicago

$s_{1}=0.5$ represent the sample deviation for Atlanta

$s_{2}=0.7$ represent the sample standard deviation for Chicago

$n_{1}=100$ sample size for the group Atlanta

$n_{2}=110$ sample size for the group Chicago

t would represent the statistic (variable of interest)

$\alpha=0.01$ significance level provided

Develop the null and alternative hypotheses for this study?

We need to conduct a hypothesis in order to check if the meanfor atlanta is different from the mean of Chicago, the system of hypothesis would be:

Null hypothesis: $\mu_{1}=\mu_{2}$

Alternative hypothesis: $\mu_{1} \neq \mu_{2}$

Since we don't know the population deviations for each group, for this case is better apply a t test to compare means, and the statistic is given by:

$t=\frac{\bar X_{1}-\bar X_{2}}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}}$ (1)

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Calculate the value of the test statistic for this hypothesis testing.

Since we have all the values we can replace in formula (1) like this:

$t=\frac{6.5-6.7}{\sqrt{\frac{0.5^2}{100}+\frac{0.7^2}{110}}}}=-2.398$

What is the p-value for this hypothesis test?

The degrees of freedom are given by:

$df = n_1 +n_2 -2= 100+110-2= 208$

Since is a bilateral test the p value would be:

$p_v =2*P(t_{208}$

Based on the p-value, what is your conclusion?

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3 years ago

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andreyandreev [35.5K]

Answer:

Decimal: 5.567764)

Step-by-step explanation:

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2 years ago