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expeople1 [14]
3 years ago
10

There were 378 visitors to the science museum on Friday. There were 409 visitors on Saturday. How many more people visited the m

useum on Saturday?
Mathematics
2 answers:
Stells [14]3 years ago
8 0
31 cause 409minus 378 is 31
JulijaS [17]3 years ago
5 0
You'll need to subtract 378 from 409


409-378=31
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barxatty [35]

Answer:

x=2.5

Step-by-step explanation:

P=(3x+1)+(x+1)+(3x+1)+(x+1)

24=3x+1+x+1+3x+1+x+1

24=8x+4

24-4=8x

20=8x

x=20/8

x=2.5

P=(3*2.5+1)+(2.5+1)+(3*2.5+1)+(2.5+1)

P=8.5+3.5+8.5+3.5

P=24

5 0
3 years ago
Purslane bought 350 rolls of toilet paper for the whole year. How many rolls of toilet paper per month is that?
siniylev [52]

Answer:

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Step-by-step explanation:

350 divided by 12 months

equals 29.

5 0
3 years ago
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Is point B a reflection across the x-axis of point C? Explain why or why not.
Black_prince [1.1K]

Answer:

no ot is not b/c both would be negative and its not the same points as B

5 0
2 years ago
hank and his two friends are attending a concert they purchase tickets and parking for a total of $ 129.00 they decide it is eas
Oksi-84 [34.3K]
First, you need to figure out how many people are paying. Since it is Hank and his two friends, three people will be paying. Next, you need to divide 129.00 by 3. 129/3=43. Each friend will pay exactly $43.00.
3 0
3 years ago
In a sample of 1000 randomly, selected consumers who had opportunities to send in a rebate claim form after purchasing a product
Alexxx [7]

Answer: =(0.2232,0.2768)

Step-by-step explanation:

The confidence interval for population proportion is given by :-

p\ \pm z_{\alpha/2}\sqrt{\dfrac{p(1-p)}{n}}

Given : Sample size : n=1000

The proportion of people selected consumers who had opportunities to send in a rebate claim form after purchasing a product said they never did so =\dfrac{250}{1000}=0.25

Significance level : 1-0.95=0.05

Critical value : z_{\alpha/2}=1.96

Now, the 95% confidence Interval for the true proportion of such consumers who never apply for a rebate will be :-

0.25\ \pm (1.96)\sqrt{\dfrac{0.25(1-0.25)}{1000}}\\\\\approx0.25\pm0.0268\\\\=(0.2232,\ 0.2768)

Hence, a confidence Interval for the true proportion of such consumers who never apply for a rebate .

8 0
3 years ago
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