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tino4ka555 [31]
3 years ago
14

When seven times a number is decreased by 66​ the result is 50. what is the​ number?

Mathematics
1 answer:
Leviafan [203]3 years ago
3 0
The number would be 24
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What is the area of the rectangle, in square feet?<br> 29<br> 58<br> 120<br> 180
Fittoniya [83]

Answer:

180

Step-by-step explanation:

Base x Height

So 9 x 20 to get 180

3 0
2 years ago
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A particle moves according to a law of motion s = f(t), t ? 0, where t is measured in seconds and s in feet.
Usimov [2.4K]

Answer:

a) \frac{ds}{dt}= v(t) = 3t^2 -18t +15

b) v(t=3) = 3(3)^2 -18(3) +15=-12

c) t =1s, t=5s

d)  [0,1) \cup (5,\infty)

e) D = [1 -9 +15] +[(5^3 -9* (5^2)+ 15*5)-(1-9+15)]+ [(6^3 -9(6)^2 +15*6)-(5^3 -9(5)^2 +15*5)] =7+ |32|+7 =46

And we take the absolute value on the middle integral because the distance can't be negative.

f) a(t) = \frac{dv}{dt}= 6t -18

g) The particle is speeding up (1,3) \cup (5,\infty)

And would be slowing down from [0,1) \cup (3,5)

Step-by-step explanation:

For this case we have the following function given:

f(t) = s = t^3 -9t^2 +15 t

Part a: Find the velocity at time t.

For this case we just need to take the derivate of the position function respect to t like this:

\frac{ds}{dt}= v(t) = 3t^2 -18t +15

Part b: What is the velocity after 3 s?

For this case we just need to replace t=3 s into the velocity equation and we got:

v(t=3) = 3(3)^2 -18(3) +15=-12

Part c: When is the particle at rest?

The particle would be at rest when the velocity would be 0 so we need to solve the following equation:

3t^2 -18 t +15 =0

We can divide both sides of the equation by 3 and we got:

t^2 -6t +5=0

And if we factorize we need to find two numbers that added gives -6 and multiplied 5, so we got:

(t-5)*(t-1) =0

And for this case we got t =1s, t=5s

Part d: When is the particle moving in the positive direction? (Enter your answer in interval notation.)

For this case the particle is moving in the positive direction when the velocity is higher than 0:

t^2 -6t +5 >0

(t-5) *(t-1)>0

So then the intervals positive are [0,1) \cup (5,\infty)

Part e: Find the total distance traveled during the first 6 s.

We can calculate the total distance with the following integral:

D= \int_{0}^1 3t^2 -18t +15 dt + |\int_{1}^5 3t^2 -18t +15 dt| +\int_{5}^6 3t^2 -18t +15 dt= t^3 -9t^2 +15 t \Big|_0^1 + t^3 -9t^2 +15 t \Big|_1^5 + t^3 -9t^2 +15 t \Big|_5^6

And if we replace we got:

D = [1 -9 +15] +[(5^3 -9* (5^2)+ 15*5)-(1-9+15)]+ [(6^3 -9(6)^2 +15*6)-(5^3 -9(5)^2 +15*5)] =7+ |32|+7 =46

And we take the absolute value on the middle integral because the distance can't be negative.

Part f: Find the acceleration at time t.

For this case we ust need to take the derivate of the velocity respect to the time like this:

a(t) = \frac{dv}{dt}= 6t -18

Part g and h

The particle is speeding up (1,3) \cup (5,\infty)

And would be slowing down from [0,1) \cup (3,5)

5 0
3 years ago
Pls help me now hurry
arlik [135]

Answer:

i believe it means c. middle

Step-by-step explanation:

tell me if this is wrong

7 0
2 years ago
Find the area of a regular octagon with an apothem of 8
xenn [34]

Answer:

308cm²

Step-by-step explanation:

Assuming the given unit is in cm

The expression for the area of a regular Octagon is

A=2(1+√2)a²

Given the apothem a = 8cm

Substituting we have

A=2(1+√2)8²

A= 2(1+1.414)64

A= 2(2.414)64

A= 308cm²

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3 years ago
I need help with this,, will give brianliest and +15 points
Anit [1.1K]

Answer:

41x² - 27x + 27

Step-by-step explanation:

Perimeter of Rectangle:

= 2(20x²-12x+4) + 2(5x²-5x+15)

= 40x²-24x+8 + 10x²-10x+30

= 50x²-34x+38

Perimeter of Triangle:

= 6x²+6x+3x+3+3x²-2x+8

= 9x²+7x+11

Difference:

(50x²-9x²)+(-34x+7x)+(38-11)

= 41x² - 27x + 27

8 0
2 years ago
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