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tino4ka555 [31]
3 years ago
14

When seven times a number is decreased by 66​ the result is 50. what is the​ number?

Mathematics
1 answer:
Leviafan [203]3 years ago
3 0
The number would be 24
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How do I do This math....-2.5-(-3.25)=
zhannawk [14.2K]

When you subtract a negative, it changes it to adding a positive.

= -2.5 - (-3.25)

= -2.5 + 3.25

= 0.75

Hope This Helped! Good Luck!

3 0
3 years ago
J.J.Bean sells a wide variety of outdoor equipment and clothing. The company sells both through mail order and via the internet.
melamori03 [73]

Answer:

99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

Step-by-step explanation:

We are given that a random sample of 16 sales receipts for mail-order sales results in a mean sale amount of $74.50 with a standard deviation of $17.25.

A random sample of 9 sales receipts for internet sales results in a mean sale amount of $84.40 with a standard deviation of $21.25.

The pivotal quantity that will be used for constructing 99% confidence interval for true mean difference is given by;

                      P.Q.  =  \frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }  ~ t__n_1_+_n_2_-_2

where, \bar X_1 = sample mean for mail-order sales = $74.50

\bar X_2 = sample mean for internet sales = $84.40

s_1 = sample standard deviation for mail-order purchases = $17.25

s_2 = sample standard deviation for internet purchases = $21.25

n_1 = sample of sales receipts for mail-order purchases = 16

n_2 = sample of sales receipts for internet purchases = 9

Also,  s_p =\sqrt{\frac{(n_1-1)\times s_1^{2}+(n_2-1)\times s_2^{2} }{n_1+n_2-2} }  =  \sqrt{\frac{(16-1)\times 17.25^{2}+(9-1)\times 21.25^{2} }{16+9-2} } = 18.74

The true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is represented by (\mu_1-\mu_2).

Now, 99% confidence interval for (\mu_1-\mu_2) is given by;

             = (\bar X_1-\bar X_2) \pm t_(_\frac{\alpha}{2}_)  \times s_p \times \sqrt{\frac{1}{n_1} +\frac{1}{n_2}}

Here, the critical value of t at 0.5% level of significance and 23 degrees of freedom is given as 2.807.

          = (74.50-84.40) \pm (2.807  \times 18.74 \times \sqrt{\frac{1}{16} +\frac{1}{9}})

          = [$-31.82 , $12.02]

Hence, 99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

5 0
3 years ago
A fruit seller has 64 oranges in some bags. each bag has 8 oranges. she sells the oranges for $2 per bag. how much does she sell
Aleksandr [31]
It is 512 because you have to multiple 64x8=512 you should have figure that out and add 512+2=514 do you get it now ?
8 0
3 years ago
Solve the equation by finding the common denominator. two and four sevenths plus seven and three ninths equals blank
kotegsom [21]

Answer:

9 19/21

Step-by-step explanation:

2 and 4/7 + 7 3/9 or 7 1/3. If you find common denominator its 21. So 2 and 12/21 and 7 7/21. If you add that would equal 9 19/21.

Hope this helps :)

7 0
2 years ago
What is the answer to this multiplication problem 650*3456
Roman55 [17]
650 * 3456 = 2,246,400 is the answer.
7 0
3 years ago
Read 2 more answers
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