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matrenka [14]
3 years ago
11

I WILL GIVE BRAINLIEST PLEASE ANSWER NO TROLLS!!! What is the length of diagonal LN in parallelogram LMNO?

Mathematics
2 answers:
love history [14]3 years ago
6 0

Answer:

x=4

y=12

therefore, the length of LN is 24.

azamat3 years ago
6 0
X is equal to 4
Y is equal to 12
So the length of LN is 24
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The price of a tv was decreased by 20% to £1440. What was the price before the decrease?
grigory [225]

Answer:

€7200

Step-by-step explanation:

20%---------1440

100%----------y

y= 100×1440/20

y= 144000/20

y= €7200

price before decrease= €7200

7 0
2 years ago
Simplify. Express your answer as a single fraction in simplest form.<br> x x<br> 5
lbvjy [14]

Answer:

\frac{x}{20}

Step-by-step explanation:

Given

\frac{x}{4} - \frac{x}{5}

The LCM of 4 and 5 is 20

= \frac{5x-4x}{20}

= \frac{x}{20}

5 0
3 years ago
Last month, Katie started training for the swim team. She swam 20 laps every day for 18 training days. This month, Katie wants t
nasty-shy [4]

She swim 20 laps every day for 18 training days

so total laps done last month = 20*18 = 360 laps

She will swim 3 more laps per training day and add more training days to her monthly schedule.

20 laps + 3 laps = 23 laps

(a)If Katie adds 5 training days to her schedule this month, will she swim 215 more laps?

18 days + 5 days more = 23 days

23 laps every day for 23 training days

so total laps = 23*23 = 529 laps. That is 169 more laps than 360 laps done last month. Hence she cannot swim 215 more laps

If Katie adds 10 more training days to her schedule this month, will she swim 215 more laps?

18 days + 10 days more = 28 days

23 laps every day for 28 training days

so total laps = 23*28 =644 laps. That is 284 more laps than 360 laps done last month. Hence she can swim 215 more laps

(c)If Katie adds 6 more training days to her schedule this month, will she swim 215 more laps?

18 days + 6 days more = 24 days

23 laps every day for 24 training days

so total laps = 23*24 =552 laps. That is 192 more laps than 360 laps done last month. Hence she cannot swim 215 more laps

Build an equation for finding the number of additional training days she needs to swim 215 more laps

Let x be the number of days more

So training days = 18 + x

215 more laps , so total laps = 360 + 215 = 575

3 more laps per training day so 20 + 3 = 23 laps per day

laps * training days = total laps

so equation becomes

23 * (18+x) = 575

Now solve for x

414 + 23x = 575

Subtract 414 from both sides

23x = 161

x= 7

so she needs 7 training days to swim 215 more laps

3 0
3 years ago
A company manufactures and sells x television sets per month. The monthly cost and​ price-demand equations are ​C(x)=72,000+60x
myrzilka [38]

Answer:

Step-by-step explanation:

Given

Cost Price c(x)=72000+60x

Price p(x)=300-\frac{x}{20}

Revenue generated R(x)=P(x)\times x

where x=no of units

R(x)=300x-\frac{x^2}{20}

To get maxima and minima differentiate R(x)

\frac{\mathrm{d} R(x)}{\mathrm{d} x}=0

\frac{\mathrm{d} R(x)}{\mathrm{d} x}=300-2\times \frac{x}{20}=0

300=2\times \frac{x}{20}

x=3000

maximum Revenue R(x)=(300-\frac{300}{20})\times 300=4,50,000

(b)Profit=Revenue - cost

Profit=xp(x)-c(x)

Profit=300x-\frac{x^2}{20}-72000-60x

Profit(z)=240x-\frac{x^2}{20}-72000

differentiate Profit to get maximum value

\frac{\mathrm{d} z}{\mathrm{d} x}=240-2\times \frac{x}{20}

x=2400

maximum Profit z=2,16,000

(c)Now company decided to tax the company $ 55 for each set

Profit (z_1)=xp(x)-c(x)-55x

z_1=300x-\frac{x^2}{20}-72000x-60x^2-55x

z_1=185x-\frac{x^2}{20}-72,000

differentiate Profit to get maximum value

\frac{\mathrm{d} z_1}{\mathrm{d} x}=0

\frac{\mathrm{d} z_1}{\mathrm{d} x}=185-\frac{2x}{20}=0

x=1850

P(z_1\ at\ x=1850)=99125

company should charge 207.5 $ for each set

         

6 0
3 years ago
I picked (-x,y) and it said it was incorrect I really do not understand this at all someone please help
Nataly [62]

Answer:

(x + 2, y - 6)

Step-by-step explanation:

its basically the rule of the translation, like x was 2 units to the right and y was 6 units down  

Can i get brainliest please? :))

hope this helped

7 0
3 years ago
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