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torisob [31]
4 years ago
6

How does the volume of a prism change if each dimension of the prism is doubled?

Mathematics
2 answers:
san4es73 [151]4 years ago
5 0
Correct!

V = A*h;
A ---> (2*2)A;
h ---> 2h;

V ---> (2*2*2)V = 8V.
ExtremeBDS [4]4 years ago
3 0
The prism has 3 dimensions. So, if you double the linear sizes ("dimensions") the volume is multiplied by 2^3=8.
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los lados menores de un triángulo rectángulo miden 90 m y 120 m respectivamente el valor del lado mayor es​
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3 years ago
For exercise 6 given that find the value of x
kramer

Answer:

23

Step-by-step explanation:

8x-77=3x+38 > 8x=3x+115 > 5x=115 > x=23

8 0
3 years ago
Which one of these formulas describes the following sequence?<br><br> 1,5,12,22,35
kati45 [8]

We can find a formula for nth term of the given sequence as follows:

1, 5, 12, 22, 35

The 1st differences between terms:

4, 7, 10, 13

The 2nd differences :

3, 3, 3

Since it takes two rounds of differences to arrive at a constant difference between terms, the nth term will be a 2nd degree polynomial of the form: a n^2 + b n + c, where c is a constant. The coefficients a, b, and the constant c can be found.

We can form the following 3 equations with 3 unknowns a, b, c:

1 = a\cdot1^2 + b\cdot1 + c\\5 = \cdot2^2 + b\cdot2 + c\\12 = a\cdot3^2 + b\cdot3 + c

Solving for a, b, c, we get:

a = 3/2, b = -1/2, c = 0

Therefore, the nth term of the given sequence is:

\boxed{ a_n = \dfrac{3}{2}n^2- \dfrac{1}{2} n}

7 0
3 years ago
Help me please, this is really hard.
Snowcat [4.5K]

The points of new triangle is (3,-2), (6,-3) and (2,-5).

<u>Step-by-step explanation:</u>

The given points in the triangle A(-3,7), B(9,3) and C(-7,-5).

The scale factor is \frac{1}{4} and centered at point (5,-5).

The formula to dilate a point that is not centered on a origin is given by,

D(x,y)=(h+t(x-h),k+t(y-t)).

where (h,k) is the center point.

To find A',

D(-3,7)=(5+\frac{1}{4}(-3-5),-5+\frac{1}{4}(7+5)).

D(-3,7)=(5+\frac{1}{4}(-8),-5+\frac{1}{4}(12)).

D(-3,7)=(5-2, -5+3).

D(-3,7)=(3,-2).

To find B',

D(9,3)=(5+\frac{1}{4}(9-5),-5+\frac{1}{4}(3+5)).

D(9,3)=(5+\frac{1}{4}(4),-5+\frac{1}{4}(8)).

D(9,3) = (5+1,-5+2).

D(9.3)=(6,-3).

To find C',

D(-7,-5)=(5+\frac{1}{4}(-7-5),-5+\frac{1}{4}(-5+5)).

D(-7,-5)=(5+\frac{1}{4}(-12),-5+\frac{1}{4}(0)).

D(-7,-5)=(5-3,-5+0).

D(-7,-5)=(2,-5).

∴ The points of new triangle is (3,-2), (6,-3) and (2,-5).

8 0
3 years ago
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