The revenue, in thousands of dollars, that a company earns selling lawnmowers can be modeled by R(x)=90x-x^2 and the company's t
otal profit, in thousands of dollars, after selling x lawnmowers can be modeled by p(x)= -x^2+30x-200 . Which function represents the company's cost, in thousands of dollars, for producing lawnmowers? (Recall that profit equals revenue minus cost.) A) C(x)= -60x^2-200
B) C(x)= 60x^2+200
C) C(x)=2x+60x^2+200
D) C(x)= -2x-60x^2-200
Profit, P is given by: P=R-C where R is the revenue C is the cost this implies that: C=R-P from the information given, the revenue and the cost functions are given by: R(x)=90x²-x
P(x)=30x²-x-200
thus the cost function will be: C(x)=R(x)-P(x)
substituting our values we shall have: C(x)=90x²-x-(30x²-x-200) C(x)=(90x²-30x²-x+x+200) C(x)=60x²+200 The answer is B
