Answer:
Step-by-step explanation:
A binary string with 2n+1 number of zeros, then you can get a binary string with 2n(+1)+1 = 2n+3 number of zeros either by adding 2 zeros or 2 1's at any of the available 2n+2 positions. Way of making each of these two choices are (2n+2)22. So, basically if b2n+12n+1 is the number of binary string with 2n+1 zeros then your
b2n+32n+3 = 2 (2n+2)22 b2n+12n+1
your second case is basically the fact that if you have string of length n ending with zero than you can the string of length n+1 ending with zero by:
1. Either placing a 1 in available n places (because you can't place it at the end)
2. or by placing a zero in available n+1 places.
0 ϵ P
x ϵ P → 1x ϵ P , x1 ϵ P
x' ϵ P,x'' ϵ P → xx'x''ϵ P
YOu have to set a proportion or do this easy method...
5/32= <span>0.15625
the you multiply </span><span>0.15625 by 800 because that is what you want to find out of...
that means the answer is 125
125 ride their bike to school...
hope that helps and you give good feedback
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Answer:
Is this a question about the laws of angle of incidence or is it just coordinates
Step-by-step explanation:
Answer:
x^2-4x+3
Step-by-step explanation:
Since the zeroes of the quadratic are 1 and 3, we can set up an equation in factored form:
(x-1)(x-3)
=x^2-4x+3
We can further check that this is the right answer by evaluating it at the vertex:
(2)^2-4*2+3=-1
Since that corresponds to the graph, the answer is x^2-4x+3
