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3 years ago

Find the x- and y- intercepts of the graph of the linear equation 3x-6y=2

Mathematics

1 answer:

bogdanovich [222]3 years ago

5 0

- Put x=0, you would get the y-intercept, so you got one point which would be (0,#)

- Put y=0, you got where the graph would touch\cross\intersect the x-axis, and the other point is (#,0)

to get x-intercept:
y=0:
3x=2 >> x=2/3

to get y-intercept:
x=0:
<span>-6y=2 >>> y = -1/3</span>

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Find the difference.

Scorpion4ik [409]

Answer:

Is that the letter (x) or Is that times?

If it is times; then the difference is:

Option "C" -12x2-x-7

Step-by-step explanation:

why, because it is not solvable

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3 years ago

The sum of 2 numbers is 65 and the difference is 7

Dahasolnce [82]

Answer:

Hello There!!

Step-by-step explanation:

The answer is=>The sum is x + y = 65

The difference is x - y = 7 .....x = 7 + y

7 + y + y = 65

7 + 2y = 65

2y = 58

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x + 29 = 65

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hope this helps,have a great day!!

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3 years ago

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2 years ago

One day, thirteen babies are born at a hospital. assuming each baby has an equal chance of being a boy or girl, what is the prob

Nadya [2.5K]

Using the binomial distribution, there is a 0.9983 = 99.83% probability that at most eleven of the thirteen babies are girls.

<h3>What is the binomial distribution formula?</h3>

The formula is:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.

n is the number of trials.

p is the probability of a success on a single trial.

For this problem, the values of the parameters are:

p = 0.5, n = 13

The probability that at most eleven of the thirteen babies are girls is:

$P(X \leq 11) = 1 - P(X > 11)$

In which

P(X > 11) = P(X = 12) + P(X = 13)

Then:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 12) = C_{13,12}.(0.5)^{12}.(0.5)^{1} = 0.0016$

$P(X = 13) = C_{13,13}.(0.5)^{13}.(0.5)^{0} = 0.0001$

So:

P(X > 11) = P(X = 12) + P(X = 13) = 0.0016 + 0.0001 = 0.0017

$P(X \leq 11) = 1 - P(X > 11) = 1 - 0.0017 = 0.9983$

0.9983 = 99.83% probability that at most eleven of the thirteen babies are girls.

More can be learned about the binomial distribution at brainly.com/question/24863377

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2 years ago

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Option B is right that is hundreds block, 2 tens block and 4 ones block.

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