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blsea [12.9K]
4 years ago
11

Simplify. (x7)^4 A. x^11 B. x^3 C. x^−28 D. x^28

Mathematics
2 answers:
dsp734 years ago
5 0
Rule: (a^b)^c = a^(b*c)
Raising an exponential to another exponent has you multiply the exponents.

So in this case,
(x^7)^4 = x^(7*4) = x^28

Answer: Choice D
Stella [2.4K]4 years ago
4 0
The answer is D x^28
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What is 10* 3.8 exponent of 6 in scientific notation
Tju [1.3M]
3.8 x 3.8 x 3.8 x 3.8 x 3.8 x 3.8 = 3010.9363843010.936384 x 10 = 30109.36384
30109.36384 = 3.01094 × 10^<span>4
</span>

hope this helps

8 0
3 years ago
What is (x+6)(x+4)(x-3) expand and simplify
mestny [16]

Answer:

x³ + 7x² - 6x - 72

Step-by-step explanation:

Given

(x + 6)(x + 4)(x - 3) ← expand the second and third factor, that is

(x + 4)(x - 3)

Each term in the second factor is multiplied by each term in the first factor, that is

x(x - 3) + 4(x - 3) ← distribute both parenthesis

= x² - 3x + 4x - 12 ← collect like terms

= x² + x - 12

Now multiply this by (x + 6) in the same way

(x + 6)(x² + x - 12)

= x(x² + x - 12) + 6(x² + x - 12) ← distribute both parenthesis

= x³ + x² - 12x + 6x² + 6x - 72 ← collect like terms

= x³ + 7x² - 6x - 72

7 0
3 years ago
REAL ANSWERS PLEASE AND NOT JUST FOR THE POINTS 20 EACH
Fed [463]
A+b=(-3n+2)+(5n-7)

=(5-3n)+(2-7)

=2n-5


Came up with the same answer as the first guy
4 0
3 years ago
Find \tan\left(\frac{17\pi}{12}\right)tan( 12 17π ​ )tangent, left parenthesis, start fraction, 17, pi, divided by, 12, end frac
uranmaximum [27]

One way to do this is to notice

\dfrac{17\pi}{12}=\dfrac\pi6+\dfrac{5\pi}4

Then

\tan\dfrac{17\pi}{12}=\tan\left(\dfrac\pi6+\dfrac{5\pi}4\right)=\dfrac{\tan\frac\pi6+\tan\frac{5\pi}4}{1-\tan\frac\pi6\tan\frac{5\pi}4}

We have

\tan\dfrac\pi6=\dfrac{\sin\frac\pi6}{\cos\frac\pi6}=\dfrac{\frac12}{\frac{\sqrt3}2}=\dfrac1{\sqrt3}

and since \tan x has a period of \pi,

\tan\dfrac{5\pi}4=\tan\left(\pi+\dfrac\pi4\right)=\tan\dfrac\pi4=1

and so

\tan\dfrac{17\pi}{12}=\dfrac{\frac1{\sqrt3}+1}{1-\frac1{\sqrt3}}=\dfrac{1+\sqrt3}{\sqrt3-1}=2+\sqrt3

7 0
4 years ago
Please help I have been stuck on this questions for time
sasho [114]
What is the question
6 0
3 years ago
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