Answer:
Length:8 m
Width:3 m
Step-by-step explanation:
<u><em>The complete question is</em></u>
If the perimeter of a rectangle is 22 meters, and the perimeter of a right triangle is 12 meters (the sides of the triangle are half the length of the rectangle, the width of the rectangle, and the hypotenuse is 5 meters). How do you solve for L and W, the dimensions of the rectangle.
step 1
<em>Perimeter of rectangle</em>
we know that
The perimeter of rectangle is equal to

we have

so

Simplify
-----> equation A
step 2
Perimeter of triangle
The perimeter of triangle is equal to


so

Multiply by 2 both sides

----> equation B
Solve the system of equations by graphing
Remember that the solution is the intersection point both graphs
using a graphing tool
The solution is the point (8,3)
see the attached figure
therefore
The dimensions of the rectangle are
Length:8 m
Width:3 m
Answer:
Step-by-step explanation:
7(x-5)²=63
(x-5)²=63/7
(x-5) = +/- 3
x = 5 + 3
or
x = 5- 3
x = 8 or 2
Answer:
I really don't know, sorry I cant help
Answer:
x=3
Step-by-step explanation:
or,x-2=1
or,x=2+1
or,x=3
Answer:
-7 and -5
Step-by-step explanation: