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VladimirAG [237]
3 years ago
9

An odd number under 50 but least 5 factors

Mathematics
1 answer:
ohaa [14]3 years ago
6 0
5,15,25,35,45,55 ext.
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Suppose the average farm owned by the farmers who joined Shays' Rebellion had an area of
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d would be the answer

Step-by-step explanation:

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Evaluate the Riemann sum for (x) = x3 − 6x, for 0 ≤ x ≤ 3 with six subintervals, taking the sample points, xi, to be the right e
NikAS [45]

The answer for number one is -3.938.


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3 years ago
A cone-shaped pile of sawdust has a base diameter of 38 feet, and is 14 feet tall. Find the volume of the pile
Romashka-Z-Leto [24]

Answer:

Given: Diameter of cone = 38 feet and height of cone = 14 feet.

Volume of cone V with radius r is one-third the area of the base B times the height h.

i,e  V = \frac{1}{3} B \cdot h = \frac{1}{3} \pi r^2h  ......[1]

,where B = \pi r^2

First find the radius(r);

Using Diameter(D) = 2r

38 =2r

Divide both side by 2 we get;

\frac{38}{2} =\frac{2r}{2}

Simplify:

19 = r

or r =19 feet

Now, substitute the value of r = 19 feet and h = 14 feet in [1]    [ Use value of  \pi = \frac{22}{7} ]

then, we have:

V = \frac{1}{3} \pi r^2h = \frac{1}{3} \cdot  \frac{22}{7} \cdot (19)^2 \cdot (14)

or

V = =\frac{1}{3}\cdot 22 \cdot 19 \cdot 19 \cdot  2 = \frac{22 \cdot 19 \cdot 19 \cdot 2}{3}

or

V = \frac{15884}{3} =5,294.66667 ≈ 5,294.67 cubic feet.

therefore, the volume of pile is; ≈ 5,294.67 cubic feet.


4 0
3 years ago
Which points are coplanar and noncollinear
yaroslaw [1]

Answer:

Non-collinear points: These points, like points X, Y, and Z in the above figure, don't all lie on the same line. Coplanar points: A group of points that lie in the same plane are coplanar. Any two or three points are always coplanar. Four or more points might or might not be coplanar.

Step-by-step explanation:

4 0
3 years ago
The average Act score follows a normal distribution, with a mean of 21.1 and a standard deviation of 5.1. What is the probabilit
ohaa [14]

Answer:

0.43% probability that the mean IQ score of 50 randomly selected people will be more than 23

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question:

\mu = 21.1, \sigma = 5.1, n = 50, s = \frac{5.1}{\sqrt{50}} = 0.7212

What is the probability that the mean IQ score of 50 randomly selected people will be more than 23

This is 1 subtracted by the pvalue of Z when X = 23. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{23 - 21.1}{0.7212}

Z = 2.63

Z = 2.63 has a pvalue of 0.9957

1 - 0.9957 = 0.0043

0.43% probability that the mean IQ score of 50 randomly selected people will be more than 23

5 0
3 years ago
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