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3 years ago

Write the equation of a line through the point (4,2) and with a slope of 1/2

Mathematics

1 answer:

malfutka [58]3 years ago

4 0

Answer:

y=1/2x

Step-by-step explanation:

Its simple and it works with the y=mx+b form.

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Consider the curve defined by the equation y=6x2+14x. Set up an integral that represents the length of curve from the point (−2,

torisob [31]

Answer:

32.66 units

Step-by-step explanation:

We are given that

$y=6x^2+14x$

Point A=(-2,-4) and point B=(1,20)

Differentiate w.r. t x

$\frac{dy}{dx}=12x+14$

We know that length of curve

$s=\int_{a}^{b}\sqrt{1+(\frac{dy}{dx})^2}dx$

We have a=-2 and b=1

Using the formula

Length of curve= $s=\int_{-2}^{1}\sqrt{1+(12x+14)^2}dx$

Using substitution method

Substitute t=12x+14

Differentiate w.r t. x

$dt=12dx$

$dx=\frac{1}{12}dt$

Length of curve= $s=\frac{1}{12}\int_{-2}^{1}\sqrt{1+t^2}dt$

We know that

$\sqrt{x^2+a^2}dx=\frac{x\sqrt {x^2+a^2}}{2}+\frac{1}{2}\ln(x+\sqrt {x^2+a^2})+C$

By using the formula

Length of curve= $s=\frac{1}{12}[\frac{t}{2}\sqrt{1+t^2}+\frac{1}{2}ln(t+\sqrt{1+t^2})]^{1}_{-2}$

Length of curve= $s=\frac{1}{12}[\frac{12x+14}{2}\sqrt{1+(12x+14)^2}+\frac{1}{2}ln(12x+14+\sqrt{1+(12x+14)^2})]^{1}_{-2}$

Length of curve= $s=\frac{1}{12}(\frac{(12+14)\sqrt{1+(26)^2}}{2}+\frac{1}{2}ln(26+\sqrt{1+(26)^2})-\frac{12(-2)+14}{2}\sqrt{1+(-10)^2}-\frac{1}{2}ln(-10+\sqrt{1+(-10)^2})$

Length of curve= $s=\frac{1}{12}(13\sqrt{677}+\frac{1}{2}ln(26+\sqrt{677})+5\sqrt{101}-\frac{1}{2}ln(-10+\sqrt{101})$

Length of curve= $s=32.66$

5 0

3 years ago

Expand and simplify<br> (x – 3)(2x - 2)

vekshin1

Answer:

2x^2 - 8x + 6

Step-by-step explanation:

2x*x+(-3x*2x)+(x*(-2))+6=

2x^2-8x+6

6 0

3 years ago

Find the selling price of a 270% bicycle with a 24% markup

Alenkinab [10]

Answer:

hm I say C yess

Step-by-step explanation:

yas yw ;) heh

5 0

3 years ago

How to graph y = 2|x + 3| - 4

mr_godi [17]

The x-intercepts and the y-intercepts of the function is that determines the graph is:

x-intercepts = (-5,0) and (-1,0)
y-intercepts = (0,2)

<h3>How do we graph the function y = f(x) of an absolute equation?</h3>

The function of an absolute equation can be graphed by determining the values of x-intercepts and the y-intercepts of the function.

From the given equation:

y = 2|x+3| - 4

To determine the y-intercepts, we need to set the values of x to zero, and vice versa for x-intercepts.

By doing so, the x-intercepts and the y-intercepts of the function is:

x-intercepts = (-5,0) and (-1,0)
y-intercepts = (0,2)

Therefore, since we know the x and y-intercepts, the graph of the absolute value can be seen as plotted below.

Learn more about determining the graph of an absolute equation here:

brainly.com/question/2166748

#SPJ1

8 0

2 years ago

The number 42 is what percent of 35

Vesna [10]

35 - 100%

42 - x

X=42×100/35=120%

120-100=20%

Answer: 20%

5 0

3 years ago