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uysha [10]
4 years ago
12

Possuo um terreno retangular cujo comprimento é igual ao triplo da largura. desejando murar esse terreno,consultei um pedreiro p

ara saber quantos tijolos deveria comprar.ele me disse que seriam necessários 130 tijolos por metro. então comprei 10 000 tijolos sabendo-se que a largura desse terreno é de 10,8 metros, sobraram ou faltam tijolos? se faltaram, quantos faltaram?
Preciso da conta
Mathematics
1 answer:
Savatey [412]4 years ago
4 0
Sua matemática seria:10.8 * 3 = 32.4
32.4 + 32.4 + 10.8 + 10.8 = 86.4
86.4 * 130 = 11,232
11,232 - 10,000 = 1,232Você precisará de mais 1,232 tijolos para concluí-lo.
Eu espero que isso ajude :)
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Which is the graph of the function f(x) = one-halfx2 + 2x – 6?
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Answer:

1/2 x^2 + 2x - 6 = 0

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so the graph intersects x axis at -6 and 2  

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Step-by-step explanation:

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4 years ago
Notación científica de 0,567
Phoenix [80]

Answer:

0,00567×10¹

Step-by-step explanation:

Para convertir a notación decimal:

0.00567×10¹

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Veseljchak [2.6K]

Answer:

The area of the rectangle <em>TOUR</em> is 80.00 unit².

Step-by-step explanation:

The area of a rectangle is computed using the formula:

Area\ of\ a\ Rectangle=length\times width

Since the dimensions of the rectangle are not provided we can compute the dimensions using the distance formula for two points.

The distance formula using the two point is:

distance=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}

Considering the rectangle <em>TOUR</em> the area formula will be:

Area of Rectangle <em>TOUR</em> = <em>TO × OU</em>

The co-ordinates of the four vertices of a triangle are:

T = (-8, 0), O = (4, 4), U = (6, -2) and R = (-6, -6)

Compute the distance between the vertices <em>T</em> and <em>O</em> as:

TO=\sqrt{(4-(-8))^{2}+(4-0)^{2}}\\=\sqrt{12^{2}+4^{2}} \\=\sqrt{160} \\=4\sqrt{10}

Compute the distance between the vertices <em>O </em>and <em>U</em> as:

OU=\sqrt{(6-4)^{2}+(-2-4)^{2}}\\=\sqrt{2^{2}+6^{2}} \\=\sqrt{40} \\=2\sqrt{10}

Compute the area of rectangle TOUR as follows:

Area\ of\ TOUR=TO\times OU\\=4\sqrt{10}\times 2\sqrt{10}\\=80\\\approx80.00 unit^{2}

Thus, the area of the rectangle <em>TOUR</em> is 80.00 unit².

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gtnhenbr [62]

Answer:

C = 5Q

Step-by-step explanation:

C = Length of Cloth in Meters (C)

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C = 5Q

Change C for the numbers under (Length of Cloth in Meters (C))
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So the new equations would be:

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20 = 5(4) ---------> 20 = 20

25 = 5(5) ---------> 25 = 25

So the only option that amkes sense is (C = 5Q)

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3 years ago
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