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aliina [53]
3 years ago
10

) find a vector parallel to the line of intersection of the planes 5x − y − 6z = 0 and x + y + z = 1.

Mathematics
1 answer:
snow_tiger [21]3 years ago
5 0
The cross product of the normal vectors of two planes result in a vector parallel to the line of intersection of the two planes.

Corresponding normal vectors of the planes are
<5,-1,-6> and <1,1,1>

We calculate the cross product as a determinant of (i,j,k) and the normal products

    i   j   k
   5 -1 -6
   1  1  1

=(-1*1-(-6)*1)i -(5*1-(-6)1)j+(5*1-(-1*1))k
=5i-11j+6k
=<5,-11,6>

Check orthogonality with normal vectors using scalar products
(should equal zero if orthogonal)
<5,-11,6>.<5,-1,-6>=25+11-36=0
<5,-11,6>.<1,1,1>=5-11+6=0

Therefore <5,-11,6> is a vector parallel to the line of intersection of the two given planes.
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Step-by-step explanation:

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3 years ago
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First, turn 4 5/8 into an improper fraction.

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7 0
3 years ago
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Answer:

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Step-by-step explanation:

we know that

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Let

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t ----> he time in hours

so

s=\frac{d}{t}

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t=\frac{d}{s}

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