Answer:
2 and - 
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Given
3y = 6x + 9 ( divide all terms by 3 )
y = 2x + 3 ← in slope- intercept form
with slope m = 2
(i)
Parallel lines have equal slopes, thus
the slope of line t is 2
(ii)
Given a line with slope m then the slope of a line perpendicular to it is
= - 
= - , thus
the slope of line r is -
You would start out with multiplying giving you 5(x+6). then you would have a product of 5x+30. hoped this helped!
Joshua pays 43.78 because he buys 22 packs. I found this by 110/5 . Then I multiplied 1.99 by 22 and got the final answer $43.78
The math I used is probably not the quickest way, but for me, the easiest.
25*5=125 25+20=45 45*7=315 125+315=440 25*4=100 440+100=540 5+7+4=16
B is your answer.
Answer:
Step-by-step explanation:
Let the solution to
2x^2 + x -1 =0
x^2+ (1/2)x -(1/2)
are a and b
Hence a + b = -(1/2) ( minus the coefficient of x )
ab = -1/2 (the constant)
A. We want to have an equation where the roots are a +5 and b+5.
Therefore the sum of the roots is (a+5) + (b+5) = a+ b +10 =(-1/2) + 10 =19/2.
The product is (a+5)(b+5) =ab + 5(a+b) + 25 = (-1/2) + 5(-1/2) + 25 = 22.
So the equation is
x^2-(19/2)x + 22 =0
2x^2-19x + 44 =0
B. We want the roots to be 3a and 3b.
Hence (3a) + (3b) = 3(a+b) = 3(-1/2) =-3/2 and
(3a)(3b) = 9(ab) =9(-1/2)=-9/2.
So the equation is
x^2 +(3/2) x -9/2 = 0
2x^2 + 3x -9 =0.
