a. The general equation for a circle centered at with radius is
The described circle has equation
We know the circle passes through the origin. This means that the equation above holds for and . The distance between any point on the circle and its center is the radius, so we can use this fact to determine :
So the circle's equation is
b. If the distance between point B and the center is less than , then B lies inside the circle. If the distance is greater than , it falls outside the circle. Otherwise, if the distance is exactly , then B lies on the circle.
The distance from B to the center is
, so , which means B falls outside the circle.
Answer:
Answer: (2a - 5 + b)5
Answer: 10 x (a - 2.5 + 0.5b)
Answer: (-2a + 5 - b) ⋅ (-5)
Answer:
.
Step-by-step explanation:
The given point is K(-7,-2).
The mapping for 270 clockwise rotation about the origin is .
The image of K(-7,-2) after a clockwise rotation is (2,-7).
When (2,-7) is shifted 3 units down, then x-coordinate will remain the same but the y-coordinate will reduce by 3 units.
The image K(-7,-2) after 270 degrees clockwise rotation followed by a shift of 3 units down is .
6% if I’m not wrong it should be very right