x° + 90° + 52.6 = 180°
<em>because</em><em> </em><em>a</em><em> </em><em>triangle</em><em> </em><em>adds</em><em> </em><em>up</em><em> </em><em>to</em><em> </em><em>1</em><em>8</em><em>0</em><em>°</em><em> </em><em>and </em><em>that</em><em> </em><em>spec</em><em>ific</em><em> </em><em>triangle</em><em> </em><em>is</em><em> </em><em>a</em><em> </em><em>right</em><em> </em><em>angle </em><em>triangle</em><em> </em><em>which</em><em> </em><em>means</em><em> </em><em>that</em><em> </em><em>it</em><em> </em><em>consist</em><em>s</em><em> </em><em>of</em><em> </em><em>angle</em><em> </em><em>adding</em><em> </em><em>up</em><em> </em><em>to</em><em> </em><em>9</em><em>0</em><em>°</em>
Answer:
4. H0: u1= u2 Ha; u1≠ u2
5. The smaller value of p supports the null hypothesis.
Step-by-step explanation:
4. The null and alternate hypotheses are
H0: u1= u2 i.e there no difference between the mean pinch strengthof the two surgeries
against the claim
Ha; u1≠ u2 i.e there a difference between the mean pinch strengthof the two surgeries
It can be written like this as well
H0: u1 -u2= 0 i.e there no difference between the mean pinch strengthof the two surgeries
against the claim
Ha; u1 -u2≠ 0 i.e there a difference between the mean pinch strengthof the two surgeries
Part 5. The test having a p- value less than 0.05 tells that the null hypothesis cannot be rejected. Theres no evidence to reject the null hypothesis.
The smaller value of p supports the null hypothesis.
Answer:-523/52
Step-by-step explanation:
Answer:
1.7320508
Step-by-step explanation:
Answer:
Step-by-step explanation:
3*n*p*6 = 18np
