The answer is D
0 is not less than or equal to -4, and in the second equation, 0 is greater than -1
Answer:
a)
b) 
Step-by-step explanation:
Previous concepts
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".
Part a
Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:
Where
and
We are interested on this probability
And the best way to solve this problem is using the normal standard distribution and the z score given by:
If we apply this formula to our probability we got this:
And we can find this probability like this:
And in order to find these probabilities we can find tables for the normal standard distribution, excel or a calculator.
Part b
For this case we select a sample size of n =32. Since the distribution for X is normal then the distribution for the sample mean
is given by:
And the new z score would be:



Answer:
C
Step-by-step explanation:
We know that function <em>h</em> represents an object's height in feet after <em>x</em> seconds.
In that case, option A) h(15) = 100 means that after 15 seconds, the object's height is 100 feet.
Option B) h(100) = 15 means that after 100 seconds, the object's height is 15 meters.
Therefore, neither A nor B are correct.
Option C) h(15) - h(0) = 100 means that between the zeroth and 15th second, their difference is 100 feet.
In other words, the object's height increased by 100 feet over the first 15-second period.
Option C is correct.
For Option D), it gives us the average rate of change. (h(15) - h(0)) / (15) = 100 means that for the first fifteen seconds, the height of the object increased at an average rate of 100 feet per second.
Answer:-8/3
Step-by-step explanation:
given xy/3
putting vales of x and y
(-2)(4)/3
-8/3