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3 years ago

ANSWER ASAP Write an equation of a line that passes through the points (2,3) and (2,-6).

1 answer:

6 0

1st you need to fine the slope using

S = y2-y1/x2-x1

S = -6 - 3/2-2

S = -9/0

S = Undefined

when we have undefined slope the equation would be a vertical lines.

Thus the equation would be the x value of the point

Thus the equation is x = 2

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A number is multiplied by 20, and that product is added to 5. The sum is equal to the product of 5 and 13.

liubo4ka [24]

Answer:

x = 3

Step-by-step explanation:

First, you will pick the first equation :

(x*20)

Then the next,

(x*20) + 5

Then the last equation,

(x*20) + 5 = 5*13

Then you solve

20x + 5 = 65

20x = 65 - 5

20x = 60

20x/20 = 60/20

x = 3

5 0

2 years ago

Simplify 6a+8b-a-3b plz

frozen [14]

5a+5b because 6a-a=5a and 8b-3b=5b. 5a+5b.

5 0

3 years ago

Read 2 more answers

Suppose we roll a fair die and let X represent the number on the die. (a) Find the moment generating function of X. (b) Use the

Likurg_2 [28]

Answer:

(a) moment generating function for X is $\frac{1}{6}\left(e^{t}+e^{2 t}+e^{2 t}+e^{4 t}+e^{5 t}+e^{6 t}\right)$

(b) $\mathrm{E}(\mathrm{X})=\frac{21}{6} \text { and } E\left(X^{2}\right)=\frac{91}{6}$

Step-by step explanation:

Given X represents the number on die.

The possible outcomes of X are 1, 2, 3, 4, 5, 6.

For a fair die, $P(X)=\frac{1}{6}$

(a) Moment generating function can be written as $M_{x}(t)$ .

$M_x(t)=\sum_{x=1}^{6} P(X=x)$

$M_{x}(t)=\frac{1}{6} e^{t}+\frac{1}{6} e^{2 t}+\frac{1}{6} e^{3 t}+\frac{1}{6} e^{4 t}+\frac{1}{6} e^{5 t}+\frac{1}{6} e^{6 t}$

$M_x(t)=\frac{1}{6}\left(e^{t}+e^{2 t}+e^{3 t}+e^{4 t}+e^{5 t}+e^{6 t}\right)$

(b) Now, find $E(X) \text { and } E\((X^{2})$ using moment generating function

$M^{\prime}(t)=\frac{1}{6}\left(e^{t}+2 e^{2 t}+3 e^{3 t}+4 e^{4 t}+5 e^{5 t}+6 e^{6 t}\right)$

$M^{\prime}(0)=E(X)=\frac{1}{6}(1+2+3+4+5+6)$

$\Rightarrow E(X)=\frac{21}{6}$

$M^{\prime \prime}(t)=\frac{1}{6}\left(e^{t}+4 e^{2 t}+9 e^{3 t}+16 e^{4 t}+25 e^{5 t}+36 e^{6 t}\right)$

$M^{\prime \prime}(0)=E(X)=\frac{1}{6}(1+4+9+16+25+36)$

$\Rightarrow E\left(X^{2}\right)=\frac{91}{6}$

Hence, (a) moment generating function for X is $\frac{1}{6}\left(e^{t}+e^{2 t}+e^{3 t}+e^{4 t}+e^{5 t}+e^{6 t}\right)$ .

(b) $\mathrm{E}(\mathrm{X})=\frac{21}{6} \text { and } E\left(X^{2}\right)=\frac{91}{6}$

6 0

4 years ago

How do you slove 3x+4y=8 in steps

gavmur [86]

3x+4y=8
Add -4y to both sides
3x+4y+−4y=8+−4y3x=−4y+8
Then you divide both sides by 3
3x/3=−4y+8/3x=−4/3y+8/3
And your answer is ...
x=−4/3y+8/3

7 0

3 years ago

Question 4 (4 points)

Verdich [7]

Answer:

its 18, 24 and 30

hope it helped

6 0

3 years ago

Read 2 more answers