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chubhunter [2.5K]
3 years ago
7

Which of the following points lies on the line 2x+3y=5?

Mathematics
1 answer:
Rudik [331]3 years ago
3 0

Answer:

Step-by-step explanation:

Sorry, your question is incomplete

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Calculate the volume of a rectangular prism with a length of 4.4 cmcm, a width of 3.1 cmcm, and a height of 6.3 cmcm. (As before
sergeinik [125]

Answer: 85.93 cm³  .

Step-by-step explanation:

We know that the volume of the rectangular prism is given by :-

V=\text{length x width x height}

Given : A rectangular prism has

length =4.4 cm,  width = 3.1 cm, and a= height =6.3 cm.

Then, the volume of the rectangular prism will be :

V=4.4\times3.1\times6.3=85.932\approx85.93\ cm^3

Hence, the volume of a rectangular prism is 85.93 cm³  .

8 0
3 years ago
Can sum on help me plzz
user100 [1]

Answer:

\frac{30x+30}{x+7} is the simplified radical expression.

Step-by-step explanation:

For this one, we have fractions in the bottom of a fraction (denominator).

So, we would multiply by \frac{1}{x+1}.

\frac{5x+5}{\frac{1}{6}x+\frac{7}{6}  }

Then Multiply by 6.

\frac{30x+30}{x+7} is the simplified radical expression.

4 0
3 years ago
Simplify 6° = 63<br><br> O A. 126<br><br> O B. 66<br><br> O C. 6-6<br><br> O D. 63
Vanyuwa [196]

Answer:

i think its c 6-6 so good luck

5 0
3 years ago
A researcher compares the effectiveness of two different instructional methods for teaching physiology. A sample of 178 students
xxTIMURxx [149]

Answer:

critical value = 1.645

The 90% confidence interval = ( -22.62, -17.58)

Step-by-step explanation:

Given that:

the sample  size n_1 = 178

the sample size n_2 = 226

the sample mean \overline x_1 = 54.4

the sample mean \overline x_2 = 74.5

population standard deviation \sigma_1 = 18.58

population standard deviation \sigma_2 = 9.52

level of significance ∝ = 1 - 0.90 = 0.10

The critical value for Z_{\alpha/2} = Z _{0.10/2} = Z_{0.005} is 1.645

For the construction of our confidence interval, we use 90% since that is used to find the critical value.

∴

The margin of error = Z \times\sqrt{\dfrac{\sigma_1^2}{n_1} + \dfrac{\sigma_2^2}{n_2}}

1.645 \times\sqrt{\dfrac{18.58^2}{178} + \dfrac{9.52^2}{226}}

1.645 \times\sqrt{\dfrac{345.2164}{178} + \dfrac{90.6304}{226}}

1.645 \times\sqrt{2.34042}

\simeq 2.52

The lower limit = ( \overline x_1 - \overline x_2) - (M.O.E)

= ( 54.4-74.5) - (2.52)

= -20.1 - 2.52

= -22.62

The upper limit = ( \overline x_1 - \overline x_2) + (M.O.E)

= ( 54.4-74.5) + (2.52)

= -20.1 + 2.52

= -17.58

The 90% confidence interval = ( -22.62, -17.58)

6 0
3 years ago
Help me with this please
Komok [63]

Answer:

I don't really know how to do that or I just don't remember

7 0
4 years ago
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