Question

What are the solutions of this quadratic equation?

Answer 1

The solutions for the given quadratic equation are:

$x = 8 \pm i$

How to find the solutions of the quadratic equation?

Here we have the quadratic equation:

$x^2 = 16x - 65$

We can rewrite it as:

$x^2 - 16x + 65 = 0$

Using Bhaskara's formulas, we get:

$x = \frac{-(-16) \pm \sqrt{(-16)^2 - 4*65} }{2} \\\\x = \frac{16 \pm \sqrt{(-4)} }{2}$

Now, remember that:

$\sqrt{-1} = i$

Then we can rewrite:

$x = \frac{16 \pm \sqrt{-1} *\sqrt{4} }{2}\\\\x = 8 \pm i$

If you want to learn more about quadratic equations:

brainly.com/question/1214333

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