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irga5000 [103]
4 years ago
5

Tan x/sec^2 x + tan x/csc^2 x​

Mathematics
1 answer:
Arada [10]4 years ago
5 0

I guess you're supposed to simplify?

\dfrac{\tan x}{\sec^2x}+\dfrac{\tan x}{\csc^2x}

=\tan x\left(\dfrac1{\sec^2x}+\dfrac1{\csc^2x}\right)

=\tan x(\cos^2x+\sin^2x)

=\tan x

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<h2>$65</h2>

Step-by-step explanation:

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Step-by-step explanation:

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