Check the picture below.
so the area of the hexagon is really just the area of two isosceles trapezoids.
![\textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} h=height\\ a,b=\stackrel{parallel~sides}{bases}\\[-0.5em] \hrulefill\\ a=2\\ b=4\\ h=2 \end{cases}\implies \begin{array}{llll} A=\cfrac{2(2+4)}{2}\implies A=6 \\\\\\ \stackrel{\textit{twice that much}}{2A = 12} \end{array}](https://tex.z-dn.net/?f=%5Ctextit%7Barea%20of%20a%20trapezoid%7D%5C%5C%5C%5C%20A%3D%5Ccfrac%7Bh%28a%2Bb%29%7D%7B2%7D~~%20%5Cbegin%7Bcases%7D%20h%3Dheight%5C%5C%20a%2Cb%3D%5Cstackrel%7Bparallel~sides%7D%7Bbases%7D%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20a%3D2%5C%5C%20b%3D4%5C%5C%20h%3D2%20%5Cend%7Bcases%7D%5Cimplies%20%5Cbegin%7Barray%7D%7Bllll%7D%20A%3D%5Ccfrac%7B2%282%2B4%29%7D%7B2%7D%5Cimplies%20A%3D6%20%5C%5C%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Btwice%20that%20much%7D%7D%7B2A%20%3D%2012%7D%20%5Cend%7Barray%7D)
Answer:
x=2
Step-by-step explanation:
x^3=8
x=2 (take the cubed root of both sides)
This can be solved by adding 8 to both sides, then taking the cubed root of both sides
Answer:
159
Step-by-step explanation:
k (9) = (2 * 
) - 3
= (2 * 81) - 3
= 162 - 3
= 159
8x+2.50=3.50
-2.50 -2.50 subtract both sides by -2.50
8x=1
8. 8 divide both sides by 8
x=1/8
Answer:
a=3x+b/4-x
Step-by-step explanation:
I dont know which variable you're supposed to solve for. But here's how i got the answer above:
Divide each term in a(4-x)=3x+b by 4-x
a(4-x)/4-x=3x/4-x+b/4-x
Then, cancel the common factor of 4-x, giving you
a=3x/4-x+b/4-x
Finally, combine the numerators over the common denominator,
giving you a=3x+b/4-x
