Draw a diagram! Lets say the width is x, then the length must be 2x.
Area = length x width
2x x x = 8sq meters
2x^2 = 8
x^2 =4
x = √4
x = 2
we found the width the length is two times the width, making it 4 meters.
Answer:
absolute max is 120 and absolute min is -8
Step-by-step explanation:
Find critical numbers
f'(x) = 3x^2 - 12x + 9 = 0
= 3(x^2 - 4x + 3) = 0
3(x-3)(x-1) = 0
(x-3) = 0 or (x-1)=0
x = 1,3
Test them!
x<1 Sign of f' on this interval is positive
1<x<3 Sign of f' on this interval is negative
x>3 Sign of f' on this interval is positive
f(x) changes from positive to negative at x = 1 which means there is a relative maximum here.
f(x) changes from negative to positive at x = 3 which means there is a relative minimum here.
Test the endpoints to find the absolute max and min.
f(-1) = -8
f(1) = 12
f(3) = 8
f(7) = 120
The absolute maximum value of f is 120 and the absolute minimum value of f is -8.
We’ll divide 1/4 by 6. So 1/4 x 1/6 is 1/24.
ANSWER:
1/24. Hope this helped. Have a great day. A thank you and (or) a brainliest is always appreciated! Goodbye!
There are a couple of things about this question that bother me.
1). BOB11111111 copied the question but didn't take the time to give us
the picture that goes with it. That bothers me.
2). If ABC is a triangle, then ABC cannot be a line. That also bothers me.
As it is, there's no way for anyone to answer the question without more
information than what we have here.
