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Pani-rosa [81]
4 years ago
7

the measures of the interior angles of a pentagon are 2x,6x,4x-6,2x-16,abd 6x+2.what is the measure, in degrees,of the largest a

ngle?
Mathematics
1 answer:
Basile [38]4 years ago
4 0
The answer is abd with 170. you gotta set all those angles sum as 540 wich is the sum of the angles for a pentagon. if you do that and solve for x=28 plug 28 in for 6x+2 you end up with 170

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Answer: The 1 goes in the hundreds place and the 4 goes in the tens place and the 5 goes in the ones place

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The Candela brothers own two pizza restaurants, one on Park Street and one on Bridge Road.
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The mean, median and mode are measures of central tendency, that is they tend to indicate the location middle of the data

Required values;

(a) The performance for the week for Park Street

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The performance for the week for Bridge Road

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The standard deviation is $<u>3250</u>

The Interquartile range is $<u>6075</u>

Reason:

The table of values that maybe used to find a solution to the question is given as follows;

\begin{array}{|l|l|l|}\mathbf{Variable} &\mathbf{Park}&\mathbf{Bridge}\\N&36&40\\Mean&6611&5989\\SE \ Mean&597&299\\StDev&3580&1794\\Minimum&800&1800\\Q_1&3600&5225\\Median&6600&6000\\Q_3&9675&7625\\Maximum&14100&8600\end{array}\right]

(a) Park Street revenue = $7,500

Bridge Road's revenue = $7,100

The two stores sold close to but below the 75th percentile

Bridge Road revenue;

The z-score is given as follows;

Z = \dfrac{x - \mu }{\sigma }

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From the Z-Table, we have;

The percentile= 0.7291

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The z-score is given as follows;

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From the Z-Table, we have;

The percentile = <u>0.5987</u>

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(b) Given that the operating cost is $3,000, frim which we have;

The subtracted value is subtracted from the mean and median to find the new value

Profit = The revenue - Cost

New mean = 6611 - 3000 = 3611

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The new median = 6600 - 3000 = 3600

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The standard deviation and the interquartile range remain the same, therefore, we have;

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The interquartile range = 9675 - 3600 = 6075

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Learn more here:

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Answer= x^2-4

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