<u>Question 4</u>
1) bisects , , and (given)
2) (an angle bisector splits an angle into two congruent parts)
3) and are right angles (perpendicular lines form right angles)
4) and are right triangles (a triangle with a right angle is a right triangle)
5) (reflexive property)
6) (HA)
<u>Question 5</u>
1) and are right angles, , is the midpoint of (given)
2) and are right triangles (a triangle with a right angle is a right triangle)
3) (a midpoint splits a segment into two congruent parts)
4) (HA)
5) (CPCTC)
<u>Question 6</u>
1) and are right angles, bisects (given)
2) (reflexive property)
3) (an angle bisector splits an angle into two congruent parts)
5) (HA)
6) (CPCTC)
7) bisects (if a segment splits an angle into two congruent parts, it is an angle bisector)
<u>Question 7</u>
1) and are right angles, (given)
2) and are right triangles (definition of a right triangle)
3) (vertical angles are congruent)
4) (transitive property of congruence)
6) (HA theorem)
7) (CPCTC)
8) bisects (definition of bisector of an angle)
Answer:
Numbers are 14 and 8
Step-by-step explanation:
Let the 2 numbers be x and y.
Write 2 equations:
x + y = 22
x - y = 6
Solve by substitution:
x = y + 6
Plug into the other equation:
(y + 6) + y = 22
2y + 6 = 22
2y = 16
y = 8
Plug into either equation:
x + 8 = 22
x = 14