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3 years ago

Easy 6th grade math

Mathematics

2 answers:

Grace [21]3 years ago

3 0

Answer:

18 in

Step-by-step explanation:

RSB [31]3 years ago

3 0

Answer:

18 in

Step-by-step explanation:

1 ft = 12 in

Hioe this helps. Pls give brainliest.

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50 POINTS PLEASE HELP

MrMuchimi

Answer:

∠ZXW and ∠ZXY are right angles

Step-by-step explanation:

Two right triangles are congruent if the hypotenuse and one corresponding leg are equal in both triangles

We have indication of:

WZ = YZ
ZX is common leg

Missing information is just confirmation that both of them are right triangles

This is:

∠ZXW and ∠ZXY are right angles

Correct answer option is B

7 0

3 years ago

Can u explain how to solve this?

svlad2 [7]

Answer: B.pi/2

ABCD is a square

=> Δ ABD is a isosceles right triangle at A

using pythago theorem, we have:

AB² + AD² = BD²

=> 2AD² = 4

⇔ AD² = 2

⇒ AD = √2

through O, draw EF parallel to AD and BC

=> EF is diameter

because EF//AD => EF = AD = √2 (because circle O is inscribed the square ABCD)

=> the area of the circle is $S=\frac{(\sqrt{2})^{2} }{4}.\pi =\frac{\pi }{2}$

Step-by-step explanation:

5 0

2 years ago

How do you find the area of this triangle?

lara [203]

To find the area of the triangle, use the area of a triangle formula: Area= 1/2(base)(height). In this image, the base of the triangle is 5.9. The height is 6.8. To find this, you multiply 1/2*6.8*5.9 which will give you answer: 20.06

5 0

3 years ago

Help me class8 (surds)

Mashcka [7]

Answer:

$\cfrac{991\sqrt{2} }{80}$

Step-by-step explanation:

For a start simplify each of the roots:

$\sqrt{72} =\sqrt{36*2} =6\sqrt{2}$
$\sqrt{50} =\sqrt{25*2} =5\sqrt{2}$
$\sqrt{128} =\sqrt{64*2} =8\sqrt{2}$
$\sqrt{98} =\sqrt{49*2} =7\sqrt{2}$

Now simplify the expression in steps:

$\sqrt{72}-\cfrac{48}{\sqrt{50} } -\cfrac{45}{\sqrt{128} } +2\sqrt{98} =$

$6\sqrt{2}-\cfrac{48}{5\sqrt{2} } -\cfrac{45}{8\sqrt{2} } +2*7\sqrt{2} =$

$6\sqrt{2}-\cfrac{48*8+45*5}{5*8\sqrt{2} } +14\sqrt{2} =$

$20\sqrt{2}-\cfrac{609}{40\sqrt{2} } =$

$20\sqrt{2}-\cfrac{609*\sqrt{2} }{40\sqrt{2} *\sqrt{2} } =$

$20\sqrt{2}-\cfrac{609\sqrt{2} }{40*2 } =$

$20\sqrt{2}-\cfrac{609\sqrt{2} }{80 } =$

$\sqrt{2} (20-7\cfrac{49}{80} )=$

$\sqrt{2} *12\cfrac{31}{80} =$

$\cfrac{991\sqrt{2} }{80}$

3 0

2 years ago

Which represents the inverse of the function f(x) = 4x?

nekit [7.7K]

Answer:

$\displaystyle h(x) = \frac{1}{4}x$

Step-by-step explanation:

Sinse in this case you are dealing with direct variation, all you are doing is taking the multiplicative inverse of 4, which is ¼:

$\displaystyle f(x) = 4x \rightarrow f^{-1}(x) = \frac{1}{4}x$

This option is not an answer choise. Perhaps there was a typographical errour.

I am joyous to assist you at any time.

5 0

2 years ago