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There are 32 students in the orchestra and twice that number in the band. There are 19 boys and 11 girls in the choir. If each s

Mnenie [13.5K]

The addition is one of the four fundamental mathematical operations, the others being subtraction, multiplication, and division. The total number of students that are in the orchestra, the band, and the choir is 126.

<h3>What is Addition?</h3>

The addition is one of the four fundamental mathematical operations, the others being subtraction, multiplication, and division. When two whole numbers are added together, the total quantity or sum of those values is obtained.

There are 32 students in the orchestra and twice that number in the band. Therefore the number of students in the band is:

Number of students in band = 2 (Number of students in Orchestra)

= 2 × 32 = 64

The number of students in the Choir is the sum of the number of boys and girls. Therefore, the number of students in the Choir is,

Number of students in the Choir = 19 + 11 = 30

Total number of students = 32 + 64 + 30 = 126

hence, the total number of students that are in the orchestra, the band, and the choir is 126.

Learn more about Addition:

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7 0

2 years ago

Find all of the points of the form (x −1) which are 4 unit from the point (3,2)

Bond [772]

Answer:

$(3+2\sqrt{2},2+2\sqrt{2}),(3-2\sqrt{2},2-2\sqrt{2})$

Step-by-step explanation:

$Points\ are\ of\ the\ form\ (x,x-1)\\\\Distance\ of\ these\ points\ from\ (3,2)=4\\\\\sqrt{(x-3)^2+(x-3)^2}=4\\\\\sqrt{(x-3)^2+(x-1-2)^2}=4\\\\\sqrt{2(x-3)^2}=4\\\\2(x-3)^2=16\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ square\ both\ the\ sides\\\\(x-3)^2=\frac{16}{2}\\\\(x-3)^2=8\\\\(x-3)=\pm 2\sqrt{2}\ \ \ \ \ \ \ \ \ \ \ square\ root\ both\ the\ sides\\\\x=3\pm 2\sqrt{2}\\\\When\ x=3+2\sqrt{2}\ \ \Rightarrow x-1=3+2\sqrt{2}-1=2+2\sqrt{2}\\\\When\ x=3-2\sqrt{2}\ \ \Rightarrow x-1=3-2\sqrt{2}-1=2-2\sqrt{2}$

4 0

3 years ago

The figure is made up of a hemisphere and a cylinder.

Goryan [66]

Data: (Cylinder)
h (height) = 8 cm
r (radius) = 5 cm
Adopting: $\pi \approx 3.14$
V (volume) = ?

Solving:(Cylinder volume)
 $V = h* \pi *r^2$
$V = 8*3.14*5^2$
$V = 8*3.14*25$
$\boxed{ V_{cylinder} = 628\:cm^3}$

Note: Now, let's find the volume of a hemisphere.

Data: (hemisphere volume)
V (volume) = ?
r (radius) = 5 cm
Adopting: $\pi \approx 3.14$

If: We know that the volume of a sphere is $V = 4 * \pi * \frac{r^3}{3}$ , but we have a hemisphere, so the formula will be half the volume of the hemisphere $V = \frac{1}{2} * 4 * \pi * \frac{r^3}{3} 
$

Formula: (Volume of the hemisphere)
 $V = \frac{1}{2} * 4 * \pi * \frac{r^3}{3}$

Solving:
$V = \frac{1}{2} * 4 * \pi * \frac{r^3}{3}$
$V = \frac{1}{2} * 4 * 3.14 * \frac{5^3}{3}$
$V = \frac{1}{2} * 4 * 3.14 * \frac{125}{3}$
$V = \frac{1570}{6}$
$\boxed{V_{hemisphere}\approx 261.6\:cm^3}$

Now, to find the total volume of the figure, add the values: (cylinder volume + hemisphere volume)

Volume of the figure = cylinder volume + hemisphere volume
Volume of the figure = 628 cm³ + 261.6 cm³
$\boxed{\boxed{Volume\:of\:the\:figure = 1517.6\:cm^3}}\end{array}}\qquad\quad\checkmark$

3 0

3 years ago

Read 2 more answers

What is a point-slope equation of the line with slope -12 that goes through the point (5,3)

laila [671]

Answer:

y-3 = -12 (x-5)

Step-by-step explanation:

The point slope form of an equation is

y-y1 = m(x-x1) where m is the slope and (x1,y1) is the point

y-3 = -12 (x-5)

7 0

3 years ago

3x-4x-14=9 Solve please

Anton [14]

Answer:

x = -23

Step-by-step explanation:

3x-4x-14=9

-x = 9 + 14

-x = 23

x = -23

5 0

3 years ago