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Elina [12.6K]
3 years ago
14

Given that cos 0 = and sin 0 = - 15 What is the value of tan0?

Mathematics
1 answer:
SSSSS [86.1K]3 years ago
3 0

Step-by-step explanation:

\because \:  \cos \theta = \sin \theta =  - 15 \\  \\  \therefore \:  \:  \: \cos \theta = - 15 \:  \:  \\  \:  \:  \:  \:  \:  \:  \: and \:  \:  \\  \:  \:  \:  \:  \:  \:  \:  \:  \sin \theta =  - 15  \\ \therefore \:  \frac{\sin \theta }{\cos \theta}  =  \frac{ - 15}{ - 15} \\ \therefore \:   \huge \purple{ \boxed{\tan \theta  = 1}}

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If (6y − 11)(6y + 11) = ay2 − b, what is the value of a?
lara31 [8.8K]
I hope this helps you

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PLZ HELPI DON'T UNDERSTAND THIS ONE.
Nastasia [14]

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Step-by-step explanation:

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What is the area where if this figurine ?ixl question
nydimaria [60]

Answer:

The area of the figure is 97 square inches

Step-by-step explanation:

In the given figure

<em>To find the area of the figure we can find </em><em>the area of the big rectangle with dimensions 7 inches and 19 inches</em><em> and subtract from it </em><em>the area of the small rectangle with dimensions 4 inches and 9 inches</em>

∵ The area o the rectangle = length × width

∵ The dimensions of the big rectangle are 7 inches and 19 inches

∴ The width = 7 inches

∴ The length = 19 inches

→ Substitute them in the rule of the area above

∵ The area of the big rectangle = 19 × 7

∴ The area of the big rectangle = 133 inches²

∵ The dimensions of the small rectangle are 4 inches and 9 inches

∴ The width = 4 inches

∴ The length = 9 inches

→ Substitute them in the rule of the area above

∵ The area of the small rectangle = 9 × 4

∴ The area of the small rectangle = 36 inches²

→ Subtract the area of the small rectangle from the area of the big

   rectangle to get the area of the green figure

∵ The area of the figure = the big area - the small area

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6 0
3 years ago
The half-life of the radioactive element unobtanium-43 is 10 seconds. If 48 grams of unobtanium-43 are initially present, how ma
natka813 [3]

Answer:

At time, 10 seconds, the mass remaining is 24 grams

At time, 20 seconds, the mass remaining is 12 grams

At time, 30 seconds, the mass remaining is 6 grams

At time, 40 seconds, the mass remaining is 3 grams

At time, 50 seconds, the mass remaining is 1.5 grams

Step-by-step explanation:

Given;

initial mass of the radioactive element  = 48 grams

half life, t = 10 seconds

time of decay (s)                          remaining mass of the  radioactive element

0 ------------------------------------------------- 48 grams

10------------------------------------------------- 24 grams

20 ------------------------------------------------- 12 grams

30 -------------------------------------------------- 6 grams

40 --------------------------------------------------- 3 grams

50 ----------------------------------------------------- 1.5 grams

60------------------------------------------------------0.75 grams

Thus;

At time, 10 seconds, the mass remaining is 24 grams

At time, 20 seconds, the mass remaining is 12 grams

At time, 30 seconds, the mass remaining is 6 grams

At time, 40 seconds, the mass remaining is 3 grams

At time, 50 seconds, the mass remaining is 1.5 grams

7 0
3 years ago
What is the integer that makes the following subtraction sentence true:<br><br> 8 −? = –1
VashaNatasha [74]
8 - ? = -1. the missing number would be 9.
7 0
3 years ago
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