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3 years ago

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The isosceles triangle theorem says \"if two sides of a triangle are congruent, then the angles opposite those sides are congrue

nt\". . . If you are using this figure to prove the isosceles triangle theorem, what would be the best strategy?

1 answer:

olga nikolaevna [1]3 years ago

4 0

Draw qs so that s is the midpoint of pr the prove pqs rqs using sss

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If m 2 n, which inequalities must be true? Check all that apply.

anzhelika [568]

Answer:

$(a)\ m+ 2.1 > n + 2.1$

$(b).\ m - (-4) > n - (-4)$

$(c)\ 9 +m> 6 + n$

Step-by-step explanation:

Given

$m > n$

Required

Select true inequalities

$(a)\ m+ 2.1 > n + 2.1$

Subtract 2.1 from both sides

$m > n$

This is true

$(b).\ m - (-4) > n - (-4)$

Open brackets

$m + 4 > n + 4$

Subtract 4 from both sides

$m > n$

$(c)\ 9 +m> 6 + n$

$m> -9+6 + n$

$m> n-3$

This is also true

8 0

3 years ago

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Proof that the identities are equal to eachother

Vikentia [17]

Answer:

Hello, hope this will help:)

6 0

3 years ago

Subtract. Your answer should be a polynomial in standard form. (6y^2-9y+4) -(-7y^2+5y+1)=(6y 2 −9y+4)−(−7y 2 +5y+1)=left parenth

kifflom [539]

Solution:
(6y^2-9y+4)-(-7y^2+5y+1)
Distribute to get rid of ( )
6y^2-9y+4+7y^2-5y-1
Combine like terms
13y^2-14y+3

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3 years ago

7. Triangles CDE and RST are similar triangles. What is

andreyandreev [35.5K]

Answer:

CD = 25 ft

Step-by-step explanation:

$\triangle CDE \sim \triangle RST$

$\therefore \frac{CD}{20}=\frac{40}{32}$

(Corresponding sides of similar triangles are in proportion)

$\therefore \frac{CD}{20}=\frac{5}{4}$

$\therefore CD = \frac{5}{\cancel 4}\times \cancel {20} \:\:\blue{\bold{5}}$

$\therefore CD = 5\times 5$

$\therefore CD = 25\: ft$

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3 years ago

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HELp ME 100 points if you awncer and branlyest

boyakko [2]

Answer:

its the middle 3

Step-by-step explanation:

B C and D

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3 years ago

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