Another day, another math problem 3

Mathematics

1 answer:

yuradex [85]1 year ago

5 0

Answer:

$2\sqrt{x+1}-3\\domain:[-1, \infty)$

Step-by-step explanation:

$g(h(x)) = 2(\sqrt{x+1})-3\\g(h(x)) = 2\sqrt{x+1} - 3\\$

the function is only defined when (x+1) >= 0 (since square root) so the domain is when x >= -1

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Step-by-step explanation:

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