Question

Another day, another math problem 3

Answer 1

Answer:

$2\sqrt{x+1}-3\\domain:[-1, \infty)$

Step-by-step explanation:

$g(h(x)) = 2(\sqrt{x+1})-3\\g(h(x)) = 2\sqrt{x+1} - 3$

the function is only defined when (x+1) >= 0 (since square root) so the domain is when x >= -1