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3 years ago

Functional traits can be shared between organisms with divergent ssu rrna sequences because

1 answer:

3 0

<span>Functional traits can be shared between organisms with divergent SSU rRNA sequences because functional traits may evolve independently, be shared through horizontal gene transfer, or be lost in divergent lineages.
Functional traits are characteristics that define our behavior.
</span>

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RNA and proteins combine in cells to form structures called ribosomes. Ribosomes contain the active site for peptide bond format

Juli2301 [7.4K]

Maybe. Just maybe, possibly i'm not sure

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3 years ago

From the right atrium through the tricuspid valve to the __(1)__ through the __(2)__ valve to the pulmonary trunk to the right a

atroni [7]

Answer:

Circulatory system

Explanation:

From the right atrium through the tricuspid valve to the right ventricle through the pulmonary sigmoid valve to the pulmonary trunk to the right and left lungs to the capillary beds of the pulmonary veins to the left atrium to the left ventricle of the heart through the mitral valve, to the aorta through the aortic semilunar valve, to the whole body, to the systemic arteries, to the capillaries of the body tissues, to the systemic veins, to the superior cava vein and inferior cava vein, which enter the right atrium of the heart.

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3 years ago

Which organelle is most likely to be missing from the cells of a leaf? A.nucleus

attashe74 [19]

I guess ribosomes are not present in leaf cells

5 0

3 years ago

First answer get Brainest

snow_lady [41]

Answer:

A translocation

Explanation:

it comes when a piece of one chromosome breaks off and attaches to another chromosome.

6 0

2 years ago

Read 2 more answers

In watermelons, bitter fruit (B) is dominant over sweet fruit (b), and yellow spots (S) are dominant over no spots (s). The gene

NikAS [45]

Answer:

A) 9:3:3:1

B) All bitter fruit, yellow spotted offsprings

C) Phenotypes are bitter yellow spotted (4), bitter no spot (4), sweet yellow spot (4), and sweet no spot (4). 1:1:1:1

Explanation:

This is a typical dihybrid cross involving two genes, one coding for fruit taste and the other for spot color. The allele for bitter taste (B) and yellow spot (S) is dominant over the allele for sweet taste (b) and no spot (s) respectively.

Hence, a heterozygous F1 resulting from a cross between an homozygous dominant (bitter fruit, yellow spot) and homozygous recessive (sweet fruit, no spot) will have a BbSs genotype. The heterozygous F1 offsprings are self-crossed and produce gametes BS, Bs, bS, bs. (See punnet square). The F2 offsprings will have the following phenotypes: Bitter fruit, yellow spot (9)

Bitter fruit, no spot (3)

Sweet fruit, yellow spot (3)

Sweet fruit, no spot (1)

Back cross between a F1 offspring (BbSs) and homozygous dominant parent (BBSS) will produce all bitter fruit, yellow spot offsprings (see attached image). BBSS (4), BBSs (4), BbSS (4), and BbSs (4) are the offsprings' genotypes.

For the back cross between a F1 offspring (BbSs) and a homozygous recessive (bbss) parent, the Phenotypes with their proportions are as follows:

Bitter fruit, yellow spot (BbSs, 4)

Bitter fruit, no spot (Bbss, 4)

Sweet fruit, yellow spot (bbSs, 4)

Sweet fruit, no spot (bbss, 4).

4 0

3 years ago