The best and most correct answer providedfrom your question about the entrance examination paper is the second option which is 2,250. The problem can be solved by:
3-1-1 : 5c3*5c1*5c1 *3!/2! = 750
<span>2-2-1 : 5c2*5c2*5c1 *3!/2! = 1500
</span>
Adding the two answers:
750 + 1500 = 2250
I hope it has come to your help.
Answer:
Triangle & semicircle
Step-by-step explanation:
Solution: The given problem is a binomial distribution.
The probability that a team member receives a scholarship is 
Therefore, the given problem follows binomial with n = 5 and p = 0.6667
Now the probability that 4 of 5 players selected are on scholarship is:



Therefore, the probability that 4 of 5 players selected are on scholarship is 0.329
312 I think, hop[e this helps