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tangare [24]
3 years ago
15

Find the product of 21 and (6.3 • 10-4)

Mathematics
1 answer:
tia_tia [17]3 years ago
8 0
21 (6.3 * 10^-4) = 
21 (6.3 * 1/10^4) =
21 (6.3/10^4) =
21 (6.3/10000) = 
21 * .00063 =
0.01323

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PtichkaEL [24]

Answer:

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Step-by-step explanation:

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3 years ago
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Use the formula below to find the value of $400 invested at 4% interest compounded monthly for 10 years. Step 1:Find the value o
Mazyrski [523]

Answer:

See below

Step-by-step explanation:

Step 1.

P = $400

r = 0.04

t = 10 years

n = 12  ( as there are 12 months in a year).

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A(10) = 400(1 + 0.04/12)^12^10

= 400 * 1.00333333^120

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3 years ago
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mihalych1998 [28]

Answer:

The sum is 10s^2t-5st^2.  With two separate sections, it is a binomial, and since the sum of the powers of the variables is 2+1=3, it has a degree of 3.

4 0
3 years ago
Translate the following phrase: Tom can spend no more than 20 dollars on his mom's birthday present. a) t>20 b) t<20 c) 20
tiny-mole [99]

Answer:

get help by a tutor

Step-by-step explanation:

5 0
3 years ago
Cl2 + 2KBr -> Br2 + 2KCl what is the reaction?
Serjik [45]

Answer:

Step-by-step explanation:

C

l

2

+

2

K

B

r

→

2

K

C

l

+

B

r

2

Given:

300

g

of

C

l

2

300

g

of

K

B

r

(a) Mass of

C

l

2

= 300g

Molecular mass of

C

l

2

= 2(35.45) = 70.906 g

/

m

o

l

No.of moles of

C

l

2

=

m

a

s

s

/

m

o

l

a

r

m

a

s

s

=

300

/

70.906

=

4.23

moles

Mass of

K

B

r

=

300

g

Molar mass of

K

B

r

=

39

+

79.9

=

118.9

g

/

m

o

l

No.of moles of

K

B

r

=

300

/

118.9

=

2.52

moles

Now,

Consider the equation:

C

l

2

+

2

K

B

r

→

2

K

C

l

+

B

r

2

1

mole of

C

l

2

= 2 moles of

K

C

l

4.23

moles of

C

l

2

= 2x4.23=

8.46

moles

2

moles of

K

B

r

= 2 moles of

K

C

l

2.52

moles of

K

B

r

=

2.52

moles

Now convert moles to mass,

Mass of

K

C

l

produced by

C

l

2

=

8.46

×

70.906

=

599.8

g

Mass of

K

C

l

produced by potassium bromide =

2.52

×

74.5

=

187.74

g

3 0
3 years ago
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