Part A:<span> What is the mean of the data? Show your work. (4 points)</span>
Part B:<span> Use your answer from Part A to calculate the mean absolute deviation for the data. Show your work. (6 points)</span>
If you are factoring it you can factor it into (x+5)^2
Answer:
- 9
Step-by-step explanation:
The average rate of change of f(x) in the closed interval [ a, b ] is

Here [a, b ] = [ - 5, 2 ], thus
f(b) = f(2) = 2² - 6(2) + 2 = 4 - 12 + 2 = - 6
f(a) = f(- 5) = (- 5)² - 6(- 5) + 2 = 25 + 30 + 2 = 57 , thus
average rate of change =
=
= - 9
Answer:
(a) There are asymptotes at x=3/2 and x=-1/3
Step-by-step explanation:
The denominator zeros can be found by factoring:
f(x) = (x +1)/((2x -3)(3x +1))
Neither of the denominator factors is cancelled by the numerator factor, so each represents a vertical asyptote, not a function hole.
The asymptotes are at the values of x where the denominator is zero:
2x -3 = 0 ⇒ x = 3/2
3x +1 = 0 ⇒ x = -1/3
Alright so
5^4m = 5^12
cancel the bases
4m=12
divide by 4
m=3