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maks197457 [2]
3 years ago
11

At 11:59 p.m on December 31st the times square ball in new york city was 725 feet above ground one minute later it was 584 feet

above the ground what is the rate of change of the all per second
Mathematics
1 answer:
Nuetrik [128]3 years ago
6 0

Answer:

it dropped -141 in 60 seconds so 141/60 = 2.35 ft per second

Step-by-step explanation:

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I’m studying for my Sat later in the month, and even using the answer key I don’t understand how to solve this question. Help?
shepuryov [24]

So with this equation, since the volume of the cylinder is 96 pi, plug that into the V variable, and since the radius of one of the marbles is 3, plug that into the r variable. From here, we can solve for x: 96\pi =24\pi +x(\frac{4}{3}\pi*3^3)

Firstly, solve the parentheses: 96\pi =24\pi +x(\frac{4}{3}\pi*27)\\ 96\pi =24\pi +x(36\pi)

Next, multiply 36 pi and x: 96\pi = 24\pi +36\pi x

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4 0
4 years ago
A point x is 34m due to east of a point Y . The bearing of a flagpole from x and Y are N18°W And N40°E respectively .
Murljashka [212]

Answer:

The distance of flag post from Y is 38.13 m

Step-by-step explanation:

Consider point Y at the intersection of both lines as shown below. Now the point X lies 34 meter from point Y in east direction.  

Now flag pole at point X lies at a bearing of N18°W. That is at point X from north, flag post makes an angle of 18° towards west.  

Similarly flag pole at point Y lies at a bearing of N40°E. That is at point Y from north, flag post makes an angle of 40° towards east.  

Consider ∆ AXY as right angle triangle. Therefore measure of angle FXY is,  

\angle AXY=\angle AXF+\angle FXY

\therefore 90 \degree=18\degree+\angle FXY

\angle FXY=72\degree

Consider ∆ BYX as right angle triangle. Therefore measure of angle FYX is,  

\angle BYX=\angle BYF+\angle FYX

\therefore 90 \degree=40\degree+\angle FYX

\angle FYX=50\degree

Refer attachment 1.  

From diagram consider the triangle FYX. To find the third angle that is ∠YFX can be calculated by using angle sum property of triangle.

∠YFX+∠FYX+∠FXY=180°

∠YFX+50°+72°=180°

∠YFX=58°

Refer attachment 2.  

Now the distance FY can be calculated using sin rule as follows,  

\frac{\sin X}{FY}=\frac{\sin F}{YX}=\frac{\sin Y}{FX}

Substituting the values,

\frac{\sin 72}{FY}=\frac{\sin 58}{34}=\frac{\sin 50}{FX}

Simplifying first two terms,

\frac{\sin 72}{FY}=\frac{\sin 58}{34}

Cross multiplying,

34\times\sin 72=FY\times \sin 58

\dfrac{34\times\sin 72}{\sin 58}=FY

FY=38.13 m

7 0
3 years ago
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