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julsineya [31]
3 years ago
5

What is 10 1/3 as a improper fraction and show your if you can.

Mathematics
1 answer:
Svetllana [295]3 years ago
3 0
1. Multiply 10 and 3 and add 1.

10(3)= 30+1= 31

2. Put the 31 over 3.

31/3

The improper fraction of 10 1/3 is 31/3.

Hope this helps!
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The Reyes want grilled chicken and tilapia for dinner. Mrs.
seropon [69]

Answer:

Kilogram of chicken = 1

Kilogram of tilapia = 3

Step-by-step explanation:

Cost of chicken = 150 per kilo

Cost of tilapia = 100 per kilo

Number of kilos of each if total cost should not exceed 450

Let :

Number of kilo of chicken = x

Number of tilapia kilo = y

The constraint :

150x + 100y ≤ 450

We could choose some reasonable values of x and y then, test the constraint ;

If x = 1 and y = 3

150(1) + 100(3) = 450

Hence,

1 kilo of chicken with 3 kilos of tilapia offers the greatest combination of Number of kilograms of tilapia and chicken that could be purchased and still satisfy the maximum cost constraint.

6 0
2 years ago
A tape diagram. There are 65 students out of 100 students who ride the bus. There are question mark students out of 800 students
SVEN [57.7K]

Answer:

<em>800÷100 = 8</em>

<em>65×8=520</em>

\frac{520}{800}

another way:

<em>100%-65%=35%</em>

<em>35% = 0.35</em>

<em>800×0.35= 280</em>

<em>800-280=</em>520

another way:

<em>65% = 0.65</em>

<em>0.65×800=</em>520

Hope it helped! :)

6 0
1 year ago
Use Euclid's division algorithm to find the HCF of 441, 567, 693
Illusion [34]
Let a = 693, b = 567 and c = 441

Now first we will find HCF of 693 and 567 by using Euclid’s division algorithm as under

693 = 567 x 1 + 126
567 = 126 x 4 + 63
126 = 63 x 2 + 0
Hence, HCF of 693 and 567 is 63

Now we will find HCF of third number i.e., 441 with 63 So by Euclid’s division alogorithm for 441 and 63

441 = 63 x 7+0
=> HCF of 441 and 63 is 63.

Hence, HCF of 441, 567 and 693 is 63.
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3 years ago
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Answer:

Is none a answer?

Step-by-step explanation:

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