No.
Since w = 8, you must replace the variable with the number associated to it.
So, it would be 5 + 8 = 58
5 + 8 is not equal to 58, it is equal to 13.
If you wanted to find out what w was, simply subtract 5 on both sides.
w = 58 - 5
1. (77+x)/2=84
2. Harold needs at least a 91
Work:
first, you multiply both sides by 2; 77+x=168
then you subtract 77 from both sides; x=91
then you plug it back in to check; (77+91)/2=84 ; 168/2=84 ; 84=84
Answer:
4/100 is the fraction
Step-by-step explanation:
there are four blue blocks shaded out of the 100
Answer:
The correct option is A.
Step-by-step explanation:
According to statement a1 = 4 and r = 3. This shows that r is greater than 1.
If r is greater than 1 than it includes integers greater than 1 or equal to 1. It does not include all the real numbers because real numbers include negative numbers also.
If starting value is 4,if we put n=0, then we get 4, but if we put a negative value than we would get a number which is not a part of our sequence. Thus the correct option is All integers where n ≥ 1....
