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MA_775_DIABLO [31]
4 years ago
6

I need help figuring out what a and b are

Mathematics
1 answer:
7nadin3 [17]4 years ago
7 0

Answer:

A=4 B=100

Step-by-step explanation:

5+0.4 (4/10)= 5.4

5.4+0.08(8/100)=5.48

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13
Sunny_sXe [5.5K]

Answer: A 13.4

Step-by-step

a^2 + b^2= c^2 4^2 + b^2 = 14^2 16+ b^2= 195 b^2= 180 b= square root of 180 b= 6 square root of 5 or 13.42

7 0
3 years ago
The figure is made up of a cylinder and a cone.
Gnoma [55]

Answer:

51*pi or 160.221

Step-by-step explanation:

total volume = volume of a cone + volume of a cylinder

total volume = 1/3* pi*r^2* height(of cone) + pi* r^2 *height(of cylinder)

total volume = 1/3 * pi * 3^2 * 5 + pi * 3^2 * 4

total volume = 51*pi = 160.221

7 0
3 years ago
Am I right or wrong (don't answer the last one!)
S_A_V [24]

Answer:

1) Distributive Property of Multiplication (The terms are distributed)

2) Addition property of equality (Adding 14 to both sides)

3) Simplifying (We simplified the expression)

4) Division property of equality (Dividing both sides by 6)

6 0
3 years ago
Read 2 more answers
Find the area of the parallelogram with vertices:________.
marin [14]

Answer:

97.98

Step-by-step explanation:

The area of the parallelogram PQR is the magnitude of the cross product of any two adjacent sides. Using PQ and PS as the adjacent sides;

Area of the parallelogram = |PQ×PS|

PQ = Q-P and PS = S-P

Given P(0,0,0), Q(4,-5,3), R(4,-7,1), S(8,-12,4)

PQ = (4,-5,3) - (0,0,0)

PQ = (4,-5,3)

Also, PS = S-P

PS = (8,-12,4)-(0,0,0)

PS = (8,-12,4)

Taking the cross product of both vectors i.e PQ×PS

(4,5,-3)×(8,-12,4)

PQ×PS = (20-36)i - (16-(-24))j + (-48-40)k

PQ×PS = -16i - 40j -88k

|PQ×PS| = √(-16)²+(-40)²+(-88)²

|PQ×PS| = √256+1600+7744

|PQ×PS| = √9600

|PQ×PS| ≈ 97.98

Hence the area of the parallelogram is 97.98

3 0
4 years ago
Find f(-3) for f(x)=3x^2+5x-14
Afina-wow [57]

Answer:

-2

Step-by-step explanation:

f(x)=3x^2+5x-14

f(-3)=3(-3)^2+5(-3)-14

f(-3)=3(-3)(-3)-15-14

f(-3)=3(9)-29

f(-3)=27-29

f(-3)=-2

8 0
3 years ago
Read 2 more answers
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