Answer:
a(14)=469762048
Step-by-step explanation:
geometric sequence= a(n)=a*r^(n-1)
we have:
a=7
r=28/7=4
So:
a(14)=7*4^(14-1)
=7*4^(13)
=469762048
hope this helps
Answer:
3(2x^2-3x+14)
Step-by-step explanation:
6x^2-9x+42
All three terms have a common factor of 3
3(2x^2-3x+14)
Now let's focus on 2x^2-3x+14 and bring down the factor 3 later
so a=2
b=-3
c=14
Let's try to find two factors for ac that multiply to be a*c and add up to be b.
ac=28
b=-3
-----
ac=7(4)=14(2)=8(2)
Even if I made these pairs with both negatives nothing would give me -3
So you can only go as far as 3(2x^2-3x+14)
Here is another thing to help you if you have ax^2+bx+c and b^2-4ac<0 then it can't be factored (over reals)
5 + 9 + 2 = 16
We choose one of sixteen, =>
A. 1/16
Answer:
A-no solution
Step-by-step explanation:
There are no values of x that make the equation true.
