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Montano1993 [528]
4 years ago
9

When you draw a circle and two of its diameters and connect the end points of the diameters what quadirateral do you get?

Mathematics
1 answer:
sergij07 [2.7K]4 years ago
3 0
A vin diagram I'm pretty sure. or maybe drugs pflucked my brain up. js
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Find three consecutive odd integers such that the sum of the 1st and 2nd number is 344
olga2289 [7]

Answer:

three consecutive odd integers are.

171, 173, 175

Step-by-step explanation:

Let x be the first term of odd integer,

Therefore, the second consecutive odd integers = x+2

Similarly, the third consecutive odd integers = x+4

Given:

The sum of the first term and second term is 344.

first term + second term = 344

Here first term is x and second term is x+2.

x+(x+2)=344

2x+2=344

2x=344-2

x=\frac{342}{2}

x=171

Therefore, the first odd integers is 171.

And the second consecutive odd integers = x+2=171+2=173

Similarly, the third consecutive odd integers = x+4=171+4=175

8 0
4 years ago
Witch equation represents a linear function
olya-2409 [2.1K]
Y=3x2+1
Hope this helped :)
5 0
3 years ago
Solve the equation on the interval [0, 2pi): 12cos^2 x-9=0<br><br><br> What to do?
siniylev [52]

Answer:

\large\boxed{x=\dfrac{\pi}{6}\ \vee\ x=\dfrac{5\pi}{6}\ \vee\ x=\dfrac{7\pi}{6}\ \vee\ x=\dfrac{11\pi}{6}}

Step-by-step explanation:

12\cos^2x-9=0\qquad\text{add 9 to both sides}\\\\12\cos^2x=9\qquad\text{divide both sides by 12}\\\\\cos^2x=\dfrac{9}{12}\\\\\cos^2x=\dfrac{9:3}{12:3}\\\\\cos^2x=\dfrac{3}{4}\to\cos x=\pm\sqrt{\dfrac{3}{4}}\\\\\cos x=\pm\dfrac{\sqrt3}{2}\\\\\text{Look at the picture}\\\\x=\dfrac{\pi}{6}\ \vee\ x=\dfrac{5\pi}{6}\ \vee\ x=\dfrac{7\pi}{6}\ \vee\ x=\dfrac{11\pi}{6}

6 0
3 years ago
What set of reflections would carry rectangle ABCD onto itself?
Furkat [3]
Answer: option <span>D) y=x, x-axis, y=x, y-axis</span>.

I first thought it was the option C) and I tried with it but it was wrong. This is how I dit it.

Option C step by step:

<span>1) Reflection over the x - axis => point with coordinates (a,b) is transformed into point with coordinates (a, -b)

2) Reflection over the line y = x  => point with coordinates (a, -b) is transformed into point with coordinates (-b,a)

3) New feflection over the x - axis => (-b,a) transforms into (-b, -a)

4) New reflection over the line y = x => (-b,-a) transforms into (-a,-b)

Which shows it is not the option C).

Then I probed with option D. Step by step:

1) Reflection over the line y = x => (a,b) → (b,a)

2) Reflection over the x-axis => (b,a) → (b,-a)

3) Reflection over the line y = x => (b,-a) → (-a,b)

4) Reflection over the y-axis => (-a,b) → (a,b).

So, this set of reflections, given by the option D) transforms any point into itself, which proofs that the option D) is the right answer.
</span>
7 0
4 years ago
What is the square root of -372
wel

Answer:

19.2873015 (Done by a calculator) <---- could be wrong

Step-by-step explanation:

And fun fact:

Negative numbers don't have real square roots since a square is either positive or 0. The square roots of numbers that are not perfect square are members of irrational numbers. This means that they can't be written as the quotient of two integers.

Hope it helps!

4 0
3 years ago
Read 2 more answers
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