Answer:
-3+(-5)
Checking our answer:
Adding this does indeed give -8
At at least one die come up a 3?We can do this two ways:) The straightforward way is as follows. To get at least one 3, would be consistent with the following three mutually exclusive outcomes:the 1st die is a 3 and the 2nd is not: prob = (1/6)x(5/6)=5/36the 1st die is not a 3 and the 2nd is: prob = (5/6)x((1/6)=5/36both the 1st and 2nd come up 3: prob = (1/6)x(1/6)=1/36sum of the above three cases is prob for at least one 3, p = 11/36ii) A faster way is as follows: prob at least one 3 = 1 - (prob no 3's)The probability to get no 3's is (5/6)x(5/6) = 25/36.So the probability to get at least one 3 is, p = 1 - (25/36) = 11/362) What is the probability that a card drawn at random from an ordinary 52 deck of playing cards is a queen or a heart?There are 4 queens and 13 hearts, so the probability to draw a queen is4/52 and the probability to draw a heart is 13/52. But the probability to draw a queen or a heart is NOT the sum 4/52 + 13/52. This is because drawing a queen and drawing a heart are not mutually exclusive outcomes - the queen of hearts can meet both criteria! The number of cards which meet the criteria of being either a queen or a heart is only 16 - the 4 queens and the 12 remaining hearts which are not a queen. So the probability to draw a queen or a heart is 16/52 = 4/13.3) Five coins are tossed. What is the probability that the number of heads exceeds the number of tails?We can divide
If its a reflection across the y axis the x value is reflected and the y value stays the same, so (-3,7)
Well I would say A because it went from 8 to 38 which is plus ten.
Answer:
y=4/5x-2
Step-by-step explanation:
here are the given points: (5,2) and (10,6)
First, let's find the slope, which is found with the equation (y2-y1)/(x2-x1)
so let's label the points
x1=5
y1=2
x2=10
y2=6
now we can substitute into the equation
m=(6-2)/(10-5)
subtract
m=4/5
so that means the slope is 4/5
Now, let's use point slope form, which is y-y1=m(x-x1) (m is the slope)
so let's substitute the numbers we know from earlier into the equation
y-2=4/5(x-5)
do distributive prop.
y-2=4/5x-4
add 2 to both sides
y=4/5x-2
hope this helps!
