What is an equation of the line that passes through the points (5, 8) and (-5, 2)?

Tisha orders a carpet for a room that measures 270 square feet. The salesman says the carpet costs $12.00 per square yard. He ex

Tomtit [17]

Answer:

What error did the salesman make?

The salesman made an error when convert 270 square feet to yards.

What should be the actual cost of the carpet?

The actual cost of the carpet is $360

Step-by-step explanation:

From the question, we are told that:Tisha orders a carpet for a room that measures 270 square feet.

This means the room needs 270 square feet of carpet

But from the question, we know that the carpet is sold in square yards

We convert square feet to square yards

For our conversion rates

3 ft = 1 yard

9 ft² = 1 square yards(yd²)

270 ft² = x

Cross Multiply

9 ft² × x = 270ft² × 1 yd²

x yd²= 270ft² × 1 yd²/9 ft²

x = 30 yd²

Hence, 270ft² = 30yd²

Cost of carpet =

1 yd² = $12.00

30 yd² =

Cross Multiply

= 30 × $12.00

= $360.00

The actual cost of the carpet is $360

What error did the salesman make?

The salesman made an error when convert 270 square feet to square yards.

He said 270 square feet = 90 square yards

But he was wrong.

270 square feet = 30 square yards.

What should be the actual cost of the carpet?

The actual cost of the carpet is $360

3 0

3 years ago

9x^3y^6/xy^6 Solve using only positive exponents

DedPeter [7]

Look at the attached picture

Hope it will help you...

Good luck on your assignment

6 0

3 years ago

Find the first five terms that correspond with the following expression. 4n + 2

Lorico [155]

Answer:

6,10,14,18,22

Step-by-step explanation:

4n+2

Let n=1 4(1)+2 = 4+2 = 6

Let n=2 4(2)+2 = 8+2 = 10

Let n=3 4(3)+2 = 12+2 = 14

Let n=4 4(4)+2 = 16+2 = 18

Let n=5 4(5)+2 = 20+2 = 22

7 0

3 years ago

An urn contains n white balls andm black balls. (m and n are both positive numbers.) (a) If two balls are drawn without replacem

Genrish500 [490]

DISCLAIMER: Please let me rename b and w the number of black and white balls, for the sake of readability. You can switch the variable names at any time and the ideas won't change a bit!

Case 1: both balls are white.

At the beginning we have $b+w$ balls. We want to pick a white one, so we have a probability of $\frac{w}{b+w}$ of picking a white one.

If this happens, we're left with $w-1$ white balls and still $b$ black balls, for a total of $b+w-1$ balls. So, now, the probability of picking a white ball is

$\dfrac{w-1}{b+w-1}$

The probability of the two events happening one after the other is the product of the probabilities, so you pick two whites with probability

$\dfrac{w}{b+w}\cdot \dfrac{w-1}{b+w-1}=\dfrac{w(w-1)}{(b+w)(b+w-1)}$

Case 2: both balls are black

The exact same logic leads to a probability of

$\dfrac{b}{b+w}\cdot \dfrac{b-1}{b+w-1}=\dfrac{b(b-1)}{(b+w)(b+w-1)}$

These two events are mutually exclusive (we either pick two whites or two blacks!), so the total probability of picking two balls of the same colour is

$\dfrac{w(w-1)}{(b+w)(b+w-1)}+\dfrac{b(b-1)}{(b+w)(b+w-1)}=\dfrac{w(w-1)+b(b-1)}{(b+w)(b+w-1)}$

Case 1: both balls are white.

In this case, nothing changes between the two picks. So, you have a probability of $\frac{w}{b+w}$ of picking a white ball with the first pick, and the same probability of picking a white ball with the second pick. Similarly, you have a probability $\frac{b}{b+w}$ of picking a black ball with both picks.

This leads to an overall probability of

$\left(\dfrac{w}{b+w}\right)^2+\left(\dfrac{b}{b+w}\right)^2 = \dfrac{w^2+b^2}{(b+w)^2}$

Of picking two balls of the same colour.

We want to prove that

$\dfrac{w^2+b^2}{(b+w)^2}\geq \dfrac{w(w-1)+b(b-1)}{(b+w)(b+w-1)}$

Expading all squares and products, this translates to

$\dfrac{w^2+b^2}{b^2+2bw+w^2}\geq \dfrac{w^2+b^2-b-w}{b^2+2bw+w^2-b-w}$

As you can see, this inequality comes in the form

$\dfrac{x}{y}\geq \dfrac{x-k}{y-k}$

With x and y greater than k. This inequality is true whenever the numerator is smaller than the denominator:

$\dfrac{x}{y}\geq \dfrac{x-k}{y-k} \iff xy-kx \geq xy-ky \iff -kx\geq -ky \iff x\leq y$

And this is our case, because in our case we have

$x=b^2+w^2$
$y=b^2+w^2+2bw$ so, y has an extra piece and it is larger
$k=b+w$ which ensures that k<x (and thus k<y), because b and w are integers, and so b<b^2 and w<w^2

4 0

3 years ago

PLEASE HELP ME!! I NEED HELP WITH THIS

Gala2k [10]

Answer: It is answer C.

Step-by-step explanation: Because of the location and angle of the line, it intersects at 9 on the y axis and 1 on the x, therefore giving you 9 over 1

3 0

3 years ago