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4 years ago

7

nikita wrote the expression 72 + 26. Bettina wrote the expression 4(72+26). Which sentence is true about the value of their expr

essions?

1 answer:

disa [49]4 years ago

4 0

Nikita's value is 4 times less than Bettina's value. I believe this is the answer.

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Ira Lisetskai [31]

128 I think is the answer

8 0

3 years ago

Determine if the function is an even function, an odd function or neither.

Fynjy0 [20]

Answer: Option a.

Step-by-step explanation:

By definition, a functioon is even when:

$f(x)=f(-x)$

And it is odd when:

$-f(x)=f(-x)$

Therefore, you can verify if the function is even substituting -x into the function:

$f(-x)=2(-x)^{4}+2(-x)^{2}\\f(-x)=2x^{4}+2x^{2}$

Then:

$-f(x)=f(-x)$

It is an even function.

5 0

4 years ago

Read 2 more answers

Using principle of mathematical induction prove that 6^-1 divisble by 5 .

salantis [7]

I suppose the claim is $5 \mid 6^n - 1$ for $n\in\Bbb N$ .

When $n=1$ , we have $6^1 - 1 = 6 - 1 = 5$ , and of course 5 divides 5.

Assume the claim holds for $n=k$ , that $5 \mid 6^k - 1$ . We want to use this to show it holds for $n=k+1$ , that $5 \mid 6^{k+1} - 1$ .

We have

$6^{k+1} - 1 = \left(6^{k+1} - 6\right) + \left(6 - 1) = 6\left(6^k - 1\right) + 5$

Since $5 \mid 6^k - 1$ , we can write $6^k - 1 = 5\ell$ for some integer $\ell$ . Then

$6^{k+1} - 1 = 6\cdot5\ell + 5 = 5(6\ell + 1)$

which is clearly divisible by 5. QED

5 0

2 years ago

Drag the factors to the correct locations on the image. Not all factors will be used.

qaws [65]

Answer:

This is correct, i just did the mastery test

Step-by-step explanation:

Trust :)

4 0

3 years ago

Definition population of a town is 4,300, and it grows with a doubling time of 10 years. What will the population be in 8 years?

alexgriva [62]

<span>The population of the town would be 6450.
</span><span>
</span>

8 0

4 years ago